If the solution of the fractional equation M-1 / X-1 = 2 about X is positive, then the value range of M is?

If the solution of the fractional equation M-1 / X-1 = 2 about X is positive, then the value range of M is?

m-1=2x-2
m=2x-1
x> 0 and X ≠ 1
m> And m ≠ 1

On the fractional equation of X, if the solution of (M + 1) of (x-1) - 3 = 1 is positive, then the value range of M
(x-1) of (M + 1) + (1-x) of 3 = 1

（m+1)/(x-1)+3/（1-x）=1
Multiply both sides of the equation by (x-1)
（m+1)-3=x-1
x=m-1
If x > 0, i.e
m-1>0
M > 1

If the solution of the fractional equation M / (x-1) + 3 / (1-x) = 1 is positive, then the value range of M is?

m/(x-1)+3/(1-x)=1
(m-3)/(x-1)=1
x-1=m-3
x=m-2>0
m>2

(x + y) × 12.5 = 9750 (Y-X) × 13 = 9750

By simplifying, we get x + y = 780
y - x = 750
∴ x = 15 ,y = 765

The length of the top and bottom of the trapezoid is 1 and 4 respectively, and the length of the two diagonals is 3 and 4 respectively. What is the area of the trapezoid

The area is six
As long as an auxiliary line is parallel to a diagonal line and intersects a point on the upper bottom and another point intersects a point on the extension line of the lower bottom, a right triangle is formed. The two right angles are 3 and 4, and the hypotenuse is 5
So the area of the triangle is 6
That's the trapezoidal area

Given the function f (x) = {| 1lgx |, 0 ＜ x ≤ 10 - 1 / 2x + 6, x > 10, if a, B, C are not equal to each other, and f (a) = f (b) = f (c), then the value range of ABC is
The function f (x) = {| 1lgx |, 0 ＜ x ≤ 10 is known
-If a, B and C are not equal to each other, and f (a) = f (b) = f (c), then the value range of ABC is 1 / 2x + 6, x > 10
A. (1,10) B (5,6) C (10,12) d (20,24) is the best process

If a, B and C are not equal to each other, let 0

A granary is a cylinder and cone with a diameter of 10 meters. The cylinder is 6 meters high and the cone is 2.1 meters high. The area and volume of the granary should be calculated

Floor area: (10 ／ 2) & # 178; × 3.14 = 78.5 (M & # 178;)
Volume: 78.5 × 6 + 78.5 × 2.1 △ 3 = 471 + 54.95 = 525.95 (m # 179;)

Given the ellipse (x ^ 2) / 2 + y ^ 2 = 1, the line L passing through point a (2,1) intersects with the ellipse, and the trajectory equation of the midpoint of the chord whose L is cut is obtained
Easy to read

[[1]]
∵ line L passes through point a (2,1)
Let l be a straight line
y=kx+1-2k
In combination with the elliptic equation, the following results can be obtained
(1+2k²)x²-4k(2k-1)x+8k(k-1)=0
Let the two ends of the chord be m (x1, kx1 + 1-2k), n (X2, kx2 + 1-2k)
From the Veda theorem, we can get: X1 + x2 = 4K (2k-1) / (1 + 2K & # 178;)
Let P (x, y) be the midpoint of the chord Mn
From the midpoint coordinate formula, we can get
2x=x1+x2=4k(2k-1)/(1+2k²)
2y=k(x1+x2)+2-4k=(2-4k)/(1+2k²)
If you divide these two equations, you can get
x/y=-2k,
That is k = - X / (2Y)
It is easy to see that the midpoint P is also on the line L: y = KX + 1-2k
By substituting k = - X / (2Y) into the above formula and eliminating K, the trajectory equation is obtained
x²+2y²-2x-2y=0
The arrangement is as follows:
[(x-1)²/0.5]+[(y-0.5)²/0.25]=1

The base of a triangle is 6 cm long. If the base is extended by 1 cm, the area of the triangle will be increased by 1.5 square cm

The original bottom of the triangle is 6 times higher than the bottom of the triangle, so the area should be 6 times 1.5
6/1*1.5=9

All odd numbers are prime numbers, and all even numbers are composite numbers______ (judge right or wrong)

Odd numbers and even numbers are classified according to whether they can be divided by 2; prime numbers and composite numbers are classified according to the number of divisors; their classification criteria are different: 1 is odd number, it has only one divisor, 1 is not prime number and composite number; 2 is even number, but it has only one and two divisors, 2 is prime number and not composite number