X plus 1 / 3 plus x minus 1 / 3 = x squared - 6 / 9

X plus 1 / 3 plus x minus 1 / 3 = x squared - 6 / 9

x+1/3+x-1/3=x^2-6/9
2x=x^2-2/3
x1=（3+√15）/3 x2=(3-√15)/3
The one above is the root

1 of (x + 3) + 1 of (x-3) = 6 of (x's square-9)

1 of (x + 3) + 1 of (x-3) = 6 of (x's square-9)
x-3+x+3=6
2x=6
x=3
It has been proved that x = 3 is an increasing root
The original equation has no solution

1 / 2 of X - 6 / x + 9 = 0, then 2 / x = ()

Solution: 1 / X & # 178; - 6 / x + 9 = 0
Because x ≠ 0, both sides of the equation are multiplied by X & # 178; at the same time
9x²-6x+1=0
(3x-1)²=0
Then 3x-1 = 0
x=1/3
Then 2 / x = 2 △ 1 / 3 = 6
So 1 / 2 of X - 6 / x + 9 = 0, then 2 / x = (6)
Hope to help you, I wish you happy

Simplified evaluation: when x = root 3, (x-4 / x + 3-x-6 / x) times 4x + 9 / X-2·

The results can be obtained by simplification

At the same time, the bus and train set out from two places 480 kilometers apart, and they met each other after three hours. It is known that the speed ratio of the bus and the truck is 5:3
To solve by proportion

Let's set the speed of passenger cars as X and that of freight cars as y
3x+3y=480 5:3=x:y
The solution of the equation is x = 100, y = 60

If a and B are unequal positive numbers K ∈ n +, then the sign of a · B ^ k + B · a ^ k - A ^ (K + 1) + B ^ (K + 1) is________

The speed of the freight car is 40% of that of the passenger car. The freight car and the passenger car go from a and B to each other. After two hours of meeting, what is the ratio of the distance traveled by the train and the passenger car

If the speed of passenger car is x, the speed of freight car is 0.4x,
The distance of bus is Y1, and that of truck is Y2,
Then (according to time equivalence) Y1 / x = Y2 / 0.4x
Y1/Y2=5/2

Given a (0,7), B (0, - 7), C (12,2), take C as a focal point to pass through the ellipse of a and B, the trajectory equation of the other focal point F of the ellipse is ()
A. y2-x248=1B. x2-y248=1C. y2-x248=1（y≤-1）D. x2-y248=1（y≤-1）

So the trajectory of point F is the lower branch of hyperbola with a and B as the focus and the real axis length of 2. Also, C = 7, a = 1, B2 = 48, and the trajectory equation of focus f is y2-x248 = 1 (Y ≤ - 1)

There are 63 kg of apples in basket a and B. after taking out 1 / 7 of basket a and 1 / 4 of basket B, there are 51 kg left. How many kg of apples are there in basket a and B?
Come on, big brother and big sister, help,

Hello
Take out 1 / 7 of them and they will be left
63 × (1-1 / 7) = 54 (kg)
Basket B Original:
(54-51) / (1 / 4-1 / 7) = 28 (kg)
A basket Original:
63-28 = 35 (kg)

What month and day is teacher's day? Which teacher's Day is this?
Teacher's Day is on September 10th. It's the 22nd teacher's day, just two days later
This teacher's Day is very grand (2006)

Teacher's Day is on September 10, the 22nd teacher's day