If the line y-kx-1 = 0 (K ∈ R) and the ellipse X25 + y2m = 1 have a common point, then the value range of M is & nbsp; () A. M ＞ 5B. 0 ＜ m ＜ 5C. M ＞ 1D. M ≥ 1 and m ≠ 5

If the line y-kx-1 = 0 (K ∈ R) and the ellipse X25 + y2m = 1 have a common point, then the value range of M is & nbsp; () A. M ＞ 5B. 0 ＜ m ＜ 5C. M ＞ 1D. M ≥ 1 and m ≠ 5

The straight line y = KX + 1 passes through the point (0, 1), and the straight line y = KX + 1 and the ellipse have a common point. Therefore, when (0, 1) on the ellipse or in the ellipse ﹥ 0 + 1m ≤ 1 ﹥ m ≥ 1 and M = 25, the curve is a circle or not an ellipse, so m ≠ 25 the value range of real number m is: m ≥ 1 and m ≠ 25, so select D

The circumference of a rectangle is 72 cm, and its length is three times of its width. What is its area?

72÷2=36
Width 36 (1 + 3) = 9cm
Length 9 × 3 = 27 cm
Area = 9 × 27 = 243cm and 178;

Given sin (a + faction) = - 1 / 2, then the value of 1 / cos (a + 7 faction) is

Sin (a + pie) = - 1 / 2
sina=1/2
therefore
1/cos（a＋7π）
=-1/cosa
=±2/√3

F (x) = x ^ 2 + (M + 4) x-2m-12 and X-axis intersect at two points, which are on the right side of point (1,0). Find the value range of real number M

First, the discriminant (M + 4) ^ 2 + 4 (2m + 12) > 0
It is concluded that m ≠ - 8
The intersection point is on the right side of (1,0)
F (1) > 0, and x = - (M + 4) / 2 > 1,
Thus m is obtained

In the function y = - 2x + 3, if x satisfies___ The image is in the first quadrant

∵ function y = - 2x + 3, image in the first, second and fourth quadrant, when y = 0, x = 32, image only in the X axis, x = 0, y = 3, so image in the first quadrant, then 0 < x < 32

(1) 5 times of a number is 8.1 less than 8 times of it?

Let this number be X
8x - 5x = 8.1
3x = 8.1
x = 8.1 ÷ 3
x = 2.7
A: the number is 2.7

If f (x) = - 2x ^ 2 + MX-3 is a decreasing function on [- 2, + ∞), find the range of F (- 1)

According to the meaning of the title, we can draw a conclusion
The symmetry axis of F (x) image x = m / 4 ≤ - 2
∴m≤-8
∴f(-1)=-2-m-3=-m-5≥-（-8）-5=3
That is, the range of F (- 1) is [3, + ∞)
This is what we need
Have a good time!

1 and 8 out of 33 divided by 11 out of 33 equals

1 and 8 out of 33 divided by 11 out of 33
=41/33x3
=41/11

How to prove that a set is a subset of another set?
How to prove that a set is a subset of another set, and how to prove that a set is not a subset of another set?

If any element in a set satisfies that the element belongs to another set, then the set is a subset of the other set. Generally speaking, we should consider the specific topic and the specific method
The most direct way to prove that a set is not a subset of another set is to take a counterexample, that is, if an element belongs to this set but does not belong to another set, then this set is not a subset of another set

5x = 1.5 equation

5x=1.5
Divide both sides of the equation by 5 to get
x=0.3