If the quadratic power of X - x + A is a complete square, then a is equal to?

If the quadratic power of X - x + A is a complete square, then a is equal to?

Let (x + m) &;
=x²+2mx+m²
=x²-x+a
Then 2m = - 1
m²=a
So m = - 1 / 2
So a = M & # 178; = 1 / 4

If the square of X + (A-1) x + 25 is a complete square of X, then a=

In both cases,
If it's the complete sum of squares, a = 11, then it's (x + 5) ^ 2
If the square difference is complete, a = - 9, then it is (X-5) ^ 2

If x square + 4 (a + 1) x + a square is a complete square, find a

X square + 4 (a + 1) x + a square
=The square of (x ± a)
therefore
=X square ± 2aX + a square
therefore
±2A=4（A+1)
Solution
A=-2
perhaps
A = - 2 / 3

Let a be a positive definite matrix of order n and B be a matrix of order n which is congruent with A. It is proved that B is also a positive definite matrix

This is the basic conclusion, which can be proved by the definition. The economic mathematics team will help you to answer it. Please evaluate it in time

The limit of infinite sequence an = (- 1 / 5) ^ n

The absolute value of the common ratio of the equal ratio sequence is less than 1
The limit of this sequence is 0

Without changing the value of the fraction, change the fraction of the fraction (1 / 5x-1 / 10Y) / (1 / 3x + 1 / 9y) into an integer (18x-9y) / (30x + 10Y)

Just multiply the numerator and denominator by 90 at the same time
The meaning of the title is to convert all fractional coefficients into integer coefficients

The domain of definition of function f (x) is d. if for any x 1, x 2 ∈ D, f (x 1) ≤ f (x 2) exists when x 1 ＜ x 2, then function f (x) is called non decreasing function on D
Let f (x) be a non decreasing function on [0,1] and satisfy the following conditions: (1) f (0) = 0; (2) f (1-x) + F (x) = 1; (3) f (x / 3) = 0.5f (x), then what is the value of F (1 / 3) + F (1 / 8). (a friend said in his reply that f (8 / 9) = 1 / 4 can be calculated from F (1 / 9) = 1 / 4, but I don't think f (8 / 9) = 3 / 4,

F (0) = 0, f (1-x) + F (x) = 1, let x = 1, so f (1) = 1, let x = 1 / 2, so f (1 / 2) = 1 / 2F (x / 3) = 0.5f (x), let x = 1, Let f (1 / 3) = 0.5f (1) = 1 / 2, let x = 1 / 3, Let f (1 / 9) = 0.5f (1 / 3) = 1 / 4, let x = 1 / 2, Let f (1 / 6) = 0.5f (1 / 2) = 1 / 4, non decreasing function property: when X1 < X2, there are f (x1)

If the image of linear function y = KX + B passes through a (0,1), B (- A * a, 3A * a), and point B is exactly on the image of inverse scale function y = - 3 / x, then K is---

Substituting point a (0,1) into a function of degree, we can get b = 1
Point B is on the image of two functions. Substituting the coordinates into the function relation, we can get - Ka & # 178; + 1 = 3A & # 178; 3 / A & # 178; = 3A & # 178;
The solution is a = ± 1 K = - 2

In rectangle ABCD, if ad = 1, ab = 3, then the acute angle formed by the two diagonals of the rectangle is______ ．

As shown in the figure, ∵ Tan ∠ BAC = bcab = 13, ∵ BAC = 30 °. Similarly, ∵ abd = 30 °. Therefore, ∵ AOD = 60 °, that is, the acute angle formed by the two diagonals of the rectangle is 60 °

If 5x-3y-2 = 0, then 105x △ 103y = 0___ ．

∵5x-3y-2=0，∴5x-3y=2，∴105x÷103y=105x-3y=102=100．