If x is known to be greater than 0 and less than 2 / 3, then the maximum value of the function y = x (2-3x) is? Don't copy it

If x is known to be greater than 0 and less than 2 / 3, then the maximum value of the function y = x (2-3x) is? Don't copy it

0

Find the maximum value of (1) y = 12 / x + 3x (x is less than 0) (2) y = 4x-9 / (2-4x) (x is greater than 1 / 2)

1）、x1/2
y=4x-9/（2-4x）=4x+9/(4x-2)=(4x-2)+9/(4x-2)+2
≥2*√【（4x-2）*9/（4x-2）】+2=8
If 4x-2 = 9 / (4x-2), then x = 5 / 4
The maximum value is 8

Let me ask: X, y satisfy x + 2Y less than = 4, X-Y less than = 1, x + 2 greater than = 0, the maximum value of objective function z = 3x-y is 5? Why?

When x + 2 ≥ 0, X ≥ - 2x-y ≤ 1, X ≤ y + 1-2 ≤ x ≤ y + 1y + 1 ≥ - 2Y ≥ - 3x + 2Y ≤ 4-2 + 2Y ≤ x + 2Y ≤ y + 1 + 2Y ≤ 4x takes the maximum value y + 1, the inequality x + 2Y ≤ 4 also holds, so the value range of 3Y + 1 ≤ 4Y ≤ 1y is - 3 ≤ y ≤ 1z = 3x-y-2-y ≤ Z ≤ 3 (y + 1) - y = 2Y + 3Z ≤ 2 + 3 = 5Z

Find the maximum or minimum value of the function y = x ^ 2-3x

y=x^2-3x=(x-3/2)^2-9/4
The minimum value is - 9 / 4, and there is no maximum value

The shape of a triangular pie is shown in the figure. How to divide it into six equal sized pieces?
Triangle cake, at most, there are several kinds to be said separately

Figure

What is the nature of translation
Such as the title

Translation
1、 Definition:
Translation is to move a figure along a certain direction for a certain distance in a plane. This kind of movement is called translation. Translation does not change the shape and size of the object
2、 Basic properties:
After translation, the corresponding line segments are parallel (or collinear) and equal, the corresponding angles are equal, and the line segments connected by the corresponding points are parallel and equal;
Translation transformation does not change the shape, size and direction of the graph

Calculation: (4x's cube, Y's Square - X's Square, Y's Cube) / (- 2x's Square, Y's Square)

=-2x+y/2

Zero vector is parallel to any vector. Can we say that zero vector is parallel to any vector

That's what I said
Parallel vectors (also called collinear vectors): non-zero vectors a and B with the same or opposite directions are called parallel vectors, denoted as a ‖ B, which specifies that the zero vector is parallel to any vector
In fact, when it defines a parallel vector, it is defined as non-zero because the zero vector is parallel to any vector. This is a special case
According to this definition, it can be said that the zero vector is the parallel vector of any vector

As shown in the figure, in △ ABC, CE ⊥ EAB is known in E, BF ⊥ AC in F, and ⊥ AEF ∽ ACB is proved

In △ ABF and △ ace, ∠ AFB = 90 °= ∠ AEC, ∠ BAF = ∠ CAE,
So, △ Abf ∽ ace,
AB / AC = AF / AE
In △ AEF and △ ACB, ∠ EAF = ∠ cab, AE / AC = AF / ab,
Therefore, △ AEF ∽ ACB

Given the function f (x) = ax-bx-2lnx, f (1) = 0, if the slope of the tangent of the image of function f (x) at x = 1 is 0, and an + 1 = f '(1An + 1) - Nan + 1, if A1 ≥ 3, we prove that an ≥ n + 2

If x ＞ 0, f (1) = A-B = 0, ｜ a = B, f ′ (x) = a + ax2-2x, the slope of the tangent line of the image of ∵ function f (x) at x = 1 is 0, ｜ f ′ (1) = 0, that is, a + A-2 = 0; The following is proved by mathematical induction: (I) when n = 1, A1 ≥ 3 = 1 + 2, the inequality holds; (II) suppose that when n = k, the inequality holds, that is, AK ≥ K + 2, ak-k ≥ 2 > 0, ｜ AK + 1 = AK (ak-k) + 1 ≥ 2 (K + 2) + 1=（ K + 3) + K + 2 > K + 3, that is to say, when n = K + 1, AK + 1 ≥ (K + 1) + 2 holds. According to (I) (II), for all n ≥ 1, an ≥ n + 2 holds