For the function f (x), if there exists x0 ∈ r such that f (x0) = x0 holds, then x0 is called the fixed point of F (x). It is known that the two fixed points of F (x) = AX2 + (B-7) x + 18 are - 3 and 2 respectively: (I) finding the value of a, B and the expression of F (x); (II) finding the value range of F (x) when the domain of F (x) is [0,1]

For the function f (x), if there exists x0 ∈ r such that f (x0) = x0 holds, then x0 is called the fixed point of F (x). It is known that the two fixed points of F (x) = AX2 + (B-7) x + 18 are - 3 and 2 respectively: (I) finding the value of a, B and the expression of F (x); (II) finding the value range of F (x) when the domain of F (x) is [0,1]

(I) according to the meaning of the problem, we get f (- 3) = - 3, f (2) = 2; that is, 9A + 21-3b-a-ab = - 3, 4A + 2b-14-a-ab = 2, the solution is a = - 3, B = 5a, B = 5  f (x) = - 3x2-2x + 18 (II) ∵ the axis of symmetry of the function f (x) is x = - 13, and the opening of the image is downward, so the function f (x) monotonically decreases in the interval [0, 1], and the value range of the function f (x) is [13, 1] 8]

For the function f (x), if x0 belongs to R and f (x0) = x0 holds, then x0 is called the fixed point of F (x)
The number has two fixed points - 1 and - 2, and the maximum value of F (x) is - 1

Let f (x) = ax ^ 2 + BX + C (A0)
If f (x) = ax ^ 2 + BX + C = x, then ax ^ 2 + (B-1) x + C = 0 has two roots - 1 and - 2, that is, a (x + 1) (x + 2) = ax ^ 2 + 3ax + 2A = 0
If B = 3A + 1, C = 2A. F (x) = ax ^ 2 + (3a + 1) x + 2A has the maximum value - 1, then a

It is known that the equation (x + 1) square + (- x + b) square = 2 has two equal real roots and the inverse scale function y = 1 / x + B
In each quadrant, y increases with the increase of X (1) find the relationship of inverse proportion function (2) if point (A.3) is on hyperbola y = 1 / x + B

(1) Y = (1 + b) / X is an increasing function
1+b

How to simplify the operation of 2.7 × 3.8-0.27 × 28?

2.7×3.8-0.27×28
=2.7x3.8-2.7x2.8
=2.7x(3.8-2.8)
=2.7x1
=2.7

The equation of a curve is x ^ (2 / 3) + y ^ (2 / 3) = 1 (x, y is a real number) to find the minimum distance from the point on the curve to the origin

x^(2/3) + y^(2/3) = 1
Then y ^ 2 = (1-x ^ (2 / 3)) ^ 3 = 1-3x ^ (2 / 3) + 3x ^ (4 / 3) - x ^ 2
The point on the curve is (x, y)
Then the distance to the origin: l (x) = √ (x ^ 2 + y ^ 2) = √ [1-3x ^ (2 / 3) + 3x ^ (4 / 3)]
=√[3(x^(2/3)-1/2)+1/4]
When x ^ (2 / 3) = 1 / 2, l (x) min = 1 / 2

The product of two prime numbers is 91 and the sum is 20. These two prime numbers are () and ()?

13 and 7

Finding the power series expansion of F (x) = 1 / x with respect to (x-1)

1/x
=1/[1-(1-x)]
So it's a series with the first term of 1 and the common ratio of 1-x
f(x)=1+(1-x)+(1-x)^2+(1-x)^3+...

7 divided by () equals 8 parts equals ()% equals (): () equals 1.75?

7 divided by (4) equals 14 out of 8, equals (175)%, equals (7): (4) equals 1.75

If the function is an odd function with domain R and period 5, and f (- 2) = 1, find the values of F (100) and f (2009)

f(0)=0
f(100)=f(20*5)=f(5)=f(0)=0
f(2009)=f(2010-1)=f(-1)
Because f (- 2) = 1
There is no solution here
Please check the title

What is the quotient of the sum of 1 and the reciprocal of one third divided by the product of 8 and 1.25
There should be a formula

3