For the function f (x), if there exists x0 ∈ r such that f (x0) = x0 holds, then x0 is called the fixed point of F (x). It is known that f (x) = AX2 + (B + 1) x + (B-1) (a ≠ 0) (1) When a = 1, B = - 2, find the fixed point of F (x)

For the function f (x), if there exists x0 ∈ r such that f (x0) = x0 holds, then x0 is called the fixed point of F (x). It is known that f (x) = AX2 + (B + 1) x + (B-1) (a ≠ 0) (1) When a = 1, B = - 2, find the fixed point of F (x)

When a = 1, B = - 2, f (x) = AX2 + (B + 1) x + (B-1) = x ^ 2-x-3
Let f (x) = x, that is, x ^ 2-x-3 = X
X = - 1 or 3

For the function f (x), if there is x0 e r and f (x0) = x0 holds, then the point (x0, x0) is called the fixed point (1)
(1) Given the fixed points (1,1) and (- 3, - 3) of the function f (x) = ax & # 178; + bx-b, find the value of a and B, and then fill in the second question. (2) for any real number B, the function f (x) = ax & # 178; + bx-b always has two different fixed points, so find the value range of real number a

(1) Substituting (1,1) and (- 3, - 3), we get
a+b-b=1
9a-3b-b=-3
The solution is a = 1, B = 3
(2) The function f (x) = ax & # 178; + bx-b always has two different fixed points,
The equation AX & # 178; + bx-b = x has two different real roots
The results show that ax & # 178; + (B-1) X-B = 0
So ⊿ = (B-1) &# 178; + 4AB > 0
　　4ab>-(b-1)²　　　　（1）
The following is a discussion of B
① If B = 0, then (1) is obviously true, and the value of a is r
② If b > 0, then (1) can be reduced to
　a>-(b-1)²/(4b)
Let g (b) = - (B-1) ² / (4b), b > 0
Then a > G (b) is equivalent to a > [g (b)] max, b > 0 (max is the maximum)
It is easy to know that [g (b)] max = 0, b > 0, so a > 0
③ If B

If 3x + ax + y + by merges the similar terms and does not contain x terms, then the value of a is

If you don't know how to do it, I'll give you a detailed answer. As for your question on the first floor, I've read it. The key is that now I have no textbook, I'm sorry

Li Bai went to buy wine from the pot. He doubled the amount when he met the shop and drank a bucket when he saw the flower. He met the shop and the flower three times and drank all the wine in the pot. How much wine was in the pot?
Want to see understand!

The original amount of wine in the pot is required, and the change of the wine in the pot and the final result are told. Add (multiply by 2) three times to reduce the amount of wine in the pot. To solve this problem, we usually start from the changed result, and use the inverse relationship between multiplication and division, addition and subtraction to gradually reverse the reduction

If ABC is not equal to 0 and the maximum value of | a | / A + B / | B | + | C | / C is m and the minimum value is n, find the value of 2013 (M + n) + m-n

When | a | / A + B / | B | + | C | / C = 1 + 1 + 1 = 3, the maximum value is m = 3
When | a | / A + B / | B | + | C | / C = - 1 + - 1 + - 1 = - 3 is the minimum value, that is, n = - 3
2013(m+n)+m-n=0+3-（-3）=6

What is three fifths minus five eighths in brackets minus one sixth

3/5-(5/8-1/6)
=3/5-5/8+1/6
=(72-75+20)/120
=17/120;
If you don't understand this question, you can ask,

Find the trajectory equation of the center m of the circle which passes through the point a (2,0) and is inscribed with the circle (x + 2) & sup2; + Y & sup2; = 36
Positive solution: X & sup2; / 9 + Y & sup2; / 5 = 1

Let the center of the big circle be o (- 2,0) and the circle m pass through the fixed point a, so R + om = R and R = 6 are fixed values, then the trajectory of M is an ellipse, the center of the circle is at the origin, and O and a are the focus. C = 2,2a = 6, a = 3, C = 3

First, find the formula in brackets, and then find the value of X (1) 432 / (3x + 4) = 1 + 8% (2) 7 * (2 / x-1) - 4 = 3

（1）432/（3x+4）=1+8%
432/(3x+4)=1.08
3x+4=432/1.08
3x+4=400
3x=396
x=132
（2）7*（2/x-1)-4=3
7*(2/x-1)=3+4
2/x-1=1
2/x=2
x=1

Simple operation 0.9 + 1.99 + 2.99 + 3.9999

0.9+1.99+2.99+3.9999
=1+2+3+4-(0.1+0.01+0.001+0.0001)
=10-0.1111
=9.8889

A simple method is used to calculate; 199.199 * 198-198.198 * 199

199.199×198-198.198×199
=1.001×199×198-1.001×198×199
=0