Factorization (x + y) (x + y-4) + 4

Factorization (x + y) (x + y-4) + 4


(x + y) (x + Y - 4) + 4
=(x + y) & # - 4 (x + y) + 4
=(x²+y²-2)²
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How to find 2x (x-3) = 5 (x-3) by factorization!


You're welcome



The generatrix length of a cone is 3, the radius of its bottom is 1, and a is a point on the circumference of its bottom. What is the shortest route from point a to point a?


3 root 3
After unfolding the cone,
First, after expansion, the degree of the center angle is R / L * 360 = 1 / 3 * 360 = 120 degrees
The shortest route is the junction of the expanded graph,
3 * radical 3



Please provide 50 different denominator addition and subtraction methods for grade five! The faster the better!


3/7 + 49/9 - 4/3
8/9 +15/36 + 1/27
12+ 5/6 – 2/9 +3
8— 5/4 + 1/4
6-3/8 – 3/8
4/7 + 5/9 + 3/7 + 5/9
5/2 -( 3/2 + 4/5 )
7/8 + ( 1/8 + 1/9 )
9+ 5/6 + 5/6
3/4 + 8/9 - 1/3
7 +5/49 + 3/14
6 +( 1/2 + 2/3 )
8 + 4/5 + 8 + 11/5
31 + 5/6 – 5/6
9/7 - ( 2/7 – 10/21 )
5/9 + 3/7 + 49/9 - 4/3
4/5 + 25/16 + 2/3 + 3/4
14 + 8/7 – 5/6 + 12/15
17/32 – 3/4 + 9/24
3 + 2/9 + 1/3
5/7 + 3/25 + 3/7
3/14 + 2/3 + 1/6
1/5 + 2/3 + 5/6
9/22 + 1/11 — 1/2
5/3 + 11/5 + 4/3
45 + 2/3 + 1/3 + 15
7/19 + 12/19 + 5/6
1/4 + 3/4 - 2/3
8/7 + 21/16 + 1/2
1/5 – 1/5 + 21
6.9+4.8+3.1 0.456+6.22+3.78 15.89+(6.75-5.8)*6
4.02+5.4+0.98 5.17-1.8-3.2 13.75-(3.75+6.48)*6
3.68+7.56-2.68 7.85+2.34-0.85+4.66 35.6-1.8-15.6-7.2
3.82+2.9+0.18+9.1 9.6+4.8-3.6 7.14-0.53-2.47
5.27+2.86-0.66+1.63 13.35-4.68+2.65 73.8-1.64-13.8-5.36
47.8-7.45+8.8 0.398+0.36+3.64 15.75+3.59-0.59+14.25
7/10 + 1/10 = 8/10 = 4/5
5/9 + 4/9 = 9/9 = 1
8/15 + 3/15 = 11/15
9/14 + 3/14 = 12/14 = 6/7
3/5 + 8/5 = 11/5
4/15 - 3/15 = 1/15
7/8 - 5/8 = 2/8 = 1/4
5/3 - 2/3 = 3/3 =1
7/8 - 4/8 = 3/8
1314/2010- 520/2010 = 794/2010 = 397/1005



The area of the middle circle below is equal to that of the rectangle. It is known that the circumference of the circle is 6.28cm, and the area of the shadow in the figure is larger


Try to guess (the width of a rectangle equals the radius of a circle): because they have the same area, the length of a rectangle equals half of the circumference of a circle, that is, 2 × 3.14 × R △ 2 = 3.14r, and R = 6.28 △ 3.14 △ 2 = 1cm, then the length of a rectangle equals 3.14cm, and the width equals 1cm



As shown in the figure, in the regular triangular prism abc-a1b1c1, ab = 1. If the dihedral angle c-ab-c1 is 60 degrees, then the distance from point C to plane ABC1 is 0______ .


As shown in the figure, in the regular triangular prism abc-a1b1c1, ab = 1. If the dihedral angle c-ab-c1 is 60 ° through C as CD ⊥ AB, D as perpendicular foot, connecting C1d, then C1d ⊥ AB, ∠ c1dc = 60 ° CD = 32, then C1d = 3, CC1 = 32. In △ cc1d, through C as CE ⊥ C1d, then CE is the distance from point C to plane ABC1, CM =



Given chord length 100m, arch height 20m radius, arc length unknown


Given chord length L = 100m, arch height h = 20m radius r, the center angle of arc C is A.R ^ 2 = (R-H) ^ 2 + (L / 2) ^ 2R ^ 2 = R ^ 2-2 * r * H + H ^ 2 + L ^ 2 / 42 * r * H = H ^ 2 + L ^ 2 / 4R = H / 2 + L ^ 2 / (8 * h) = 20 / 2 + 100 ^ 2 / (8 * 20) = 72.5ma = 2 * arc sin ((L / 2) / R) = 2 * arc sin ((100 / 2) / 72.5) =



A simple summation problem of higher one sequence
If the first n terms of sequence {an} and Sn = 3an + 1, then the general term formula an =?
(n are all corner marks)


Sn = 3 [SN-S (n-1)] + 12sn = 3S (n-1) - 12sn-2 = 3S (n-1) - 3, so (sn-1) * [S (n-1) - 1] = 3 / 2sn-1 is an equal ratio sequence, q = 3 / 2S1 = a1s1 = 3s1 + 1S1 = - 1 / 2s1-1 = - 3 / 2Sn = (- 3 / 2) * (3 / 2) ^ (n-1) = - (3 / 2) ^ ns (n-1) = - (3 / 2) ^ (n-1) an = SN-S (n-1) = (- 3 / 2) * (3 / 2) ^ (n-1) -



Ask the wanderer to recite Ancient Poems
An ancient poem sung by a wanderer


Time: Tang Dynasty
[author]: Meng Jiao
[tizai]: Yuefu
[content]:--------------------
The thread in the mother's hand is the coat of the wanderer's body
I'm afraid I'll be late when I leave
Who said inch grass heart, reported three spring



Application of inverse proportion function
A garment factory plans to complete a task of producing 1600 pieces of xialiang small shirts in t (T > 4) days. If the goods are delivered four days in advance, how many pieces of xialiang small shirts will the garment factory have to make every day to complete the task?


You don't have to ask for real numbers. You can use a band
Four days ahead of time, that is, the clothes to be made in four days are evenly divided into T-4
4w/t-4