The computer uses the binary number, it has two numbers 0, 1, a decimal number into a binary number. 24 is converted into a binary number ()

The computer uses the binary number, it has two numbers 0, 1, a decimal number into a binary number. 24 is converted into a binary number ()

eleven thousand

If 1A + 1b = 4, then a − 3AB + B2A + 2B − 7ab=______ ．

∵ 1A + 1b = 4, ∵ a + B = 4AB, then a − 3AB + B2A + 2B − 7ab = a + B − 3ab2 (a + b) − 7ab = 4AB − 3ab8ab − 7ab = 1

The function f (x) = e | x-a | (a is a constant). If f (x) is an increasing function in the interval [1, + ∞), then the value range of a is
But I still don't know if it has nothing to do with whether e is less than 1····

A:
f(x)=e^|x-a|
1) When x-a = a, f (x) = e ^ (x-a) is a monotone increasing function
According to the meaning of the title: x > = 1 > = a
So: a

If a & # 178; + B = 15 AB, B & # 178; + a = 27, find the value of a + B

If a + B = 15 AB, B + a = 27 AB, then (a + b) + (a + b) - 42 = 0, then (a + b) = - 7 or + 6

What is the square of the difference between root 6 and 3
And then there's the square root

Building owner:
Original formula = (√ 6) - 3

X ^ 2 + x ^ 2 / 1-3 (x + X / 1) + 2 = 0 to solve the equation
come on. ↖ (^ω^) ↗

This is the case of 178; + 1 / x-178; + 1 / X / x-178; + 1 / x-3 (x + 1 / x) + 3 (x + 1 / x) + 3 (x + 1 / x) + 2 = 0 (x + 1 / x) - 3 (x + 1 / x) - 3 (x + 1 / x) (x + 1 / x-3) (x + 1 / x-3) (x + 1 / X-1 / x-3) (x + 1 / x-178; + 1 (rounding off) x + 1 (to be left) x + 1 / X-1 / X-1 / x-3-3-3-3 (x-3 / 3 / 2) - this is the case of 178; this is the case of 178; 178; = -1 + (3 (3 (3 / 3 / 2) (3 / 3 / 3 / 2) (3 / 3 / 2) (3 / 2) (3 / 3 / 2) - this is the final (3 / 3 / 2) - this is the feature feature 178; (178; = -3 (3 3 - √ 5) / 2

Let a = (A1, A2, A3, A4) be a square matrix of order 4, AI be the i-th column vector of a, let B = (a1-a2, A2)-
Let a = (A1, A2, A3, A4) be a square matrix of order 4, AI be the ith column vector of a, let B = (a1-a2, A2-A3, a3-a4, a4-a1), then | B | =?

The determinant of B is 0
Add the first three columns to the last column, the last column is 0, and the determinant is 0

Solve the equation with the specified method: (1) x2 + 4x-1 = 0 (formula method) (2) 6x2-x-12 = 0 (collocation method)

(1) X2 + 4x-1 = 0, b2-4ac = 42-4 × 1 × (- 1) = 20, x = − 4 ± 202, X1 = - 2 + 5, X2 = - 2-5. (2) 6x2-x-12 = 0, 6x2-x = 12, x2-16x = 2, formula: x2-16x + (112) 2 = 12 + (112) 2, (x-112) 2 = (1712) 2, formula: x-112 = ± 1712, X1 = 32, X2 = - 43

Let the population x obey the normal distribution, n (52,6.3 ^ 2), (x1, X2,..., X36) be a sample from the population x, and the mean value is XO, then p {50.8} can be obtained

XO obeys normal distribution, n (52,6.3 ^ 2 / 36), so (xo-52) / (6.3 / 6) obeys standard normal distribution

If the polynomial x ^ 2-mx + 9 is a complete square, then the value of M is ()
A.-3
B.-6
C. Plus or minus 3
D. Plus or minus 6

Choose D