Ask for a marketing plan book of XXX enterprise, 5000 words urgent! For a marketing plan of XXX enterprise, 5000 words, thank you!

Ask for a marketing plan book of XXX enterprise, 5000 words urgent! For a marketing plan of XXX enterprise, 5000 words, thank you!

What kind of enterprise? What kind of industry? Current situation? What problems need to be solved? We should make it clear
Besides, I'm afraid 20 points will not be given to you for such a marketing plan, unless there is a ready-made one for your reference

The proposal for reading culture festival is 150-200 words,

When you walk into a bookshop full of books and choose a good book to read tirelessly, when you hold a favorite book in your hand and share the wonderful reading time with your peers, when you prepare a library for yourself to collect wisdom and enjoy the pleasure of wandering in the ocean of knowledge, you will take reading as a responsibility, Regard reading as a kind of nutrient to enrich life and a ship to the other side of ideal
If you want to have a perfect and intelligent life, you can start with reading. A book is a magic treasure. Open it, there are not only astronomy and geography, natural conditions, but also folk customs and bustling life Reading, can change a person's thinking and soul, reading, can change a person's attitude towards life, reading, can change a person's habits
Bacon said: reading is enough to be joyful, erudite and talented. Its pleasure is most seen in solitude; its erudition is most seen in eloquence; its talent is most seen in the judgment of life. Walking with classics, making a good life background, and accompanying with famous works, shaping a beautiful soul. Reading is like playing a wonderful music of life, with clear ambition and bright awakening, There are the melodious of wisdom, the excitement of creation and the resonance of happiness, anger and sadness
Choose one!

Equation X-5 / 2x = 9 (2 + 7 / 4) x = 7 / 5 4x * 10 / 7 = 14 x divided by 5 / 7 = 8 / 5 / 3 / 1
*=Multiply by / equal to fraction line

33217

If a (1,2) and B (3,5) are known, then the vector AB translated by (- 1,3) is ()
A.（1,6）
B.（0,5）
C.（－4,3）
D.（2,3）

The vector AB = (2,3) the coordinate is invariant after the vector is translated
DDDD

As shown in the figure, it is known that △ ABC is an equilateral triangle, D is the midpoint of side AC, connecting BD, EC ⊥ BC to point C, CE = BD

It is proved that: ∵ ABC is an equilateral triangle, D is the middle point of edge AC, ∵ BD ⊥ AC, that is, ∵ ADB = 90 °, ∵ EC ⊥ BC, ∵ BEC = 90 °, ∵ DBC + DCB = 90 °, ∵ ECD + BCD = 90 °, ∵ ace = DBC, ∵ in △ CBD and △ ace, BD = CE ∠ DBC = acebc = AC ≌ CBD ≌ RT △ AC

Known: a = 10000, B = 9999, find the value of A2 + b2-2ab-6a + 6B + 9

∵ a = 10000, B = 9999, ∵ A-B = 10000-9999 = 1, then the original formula = (a-b) 2-6 (a-b) + 9 = 1-6 + 9 = 4

The elliptic standard equation passing through point a (- 1, - 2) and having the same focus as the ellipse (xsquare) / 6 + (ysquare) / 9 = 1 is?
The elliptic standard equation passing through point a (- 1, - 2) and having the same focus as the ellipse X & sup2 / 6 + Y & sup2 / 9 = 1 is?

Let the ellipse be x ^ 2 / b ^ 2 + y ^ 2 / A ^ 2 = 1
The easily obtained focus is on the Y-axis and is (0, ± root sign 3)
b^2=a^2-3
Take a (- 1, - 2) to get
a^2=6
b^2=3
So the ellipse is x ^ 2 / 3 + x ^ 2 / 6 = 1

In the triangle ABC, the angle ABC > angle BCA ad perpendicular to D P is any point of AD

By Pythagorean theorem, there are: ab ^ 2 = ad ^ 2 + BD ^ 2, AC ^ 2 = ad ^ 2 + CD ^ 2, Pb ^ 2 = PD ^ 2 + BD ^ 2, PC ^ 2 = PD ^ 2 + CD ^ 2, assuming AC + BP ≥ AB + PC, then: √ (AD ^ 2 + CD ^ 2) ＋ √

The imaginary number Z satisfies the condition | 2Z + 15 | = √ 3 | (z) + 10 |,
1. Find the value of | Z |
2. If Z / A + A / Z is a real number, find the value of real number a
How do you do it?

z=m+ni
|2z+15|=√3|z＋10|
|2z+15|^2=3|z＋10|^2
|2z+15|^2=|(2m+15)+2ni|^2=(2m+15)^2+4n^2
|z+10|^2=|(m+10)+ni|^2=(m+10)^2+n^2
So 4m ^ 2 + 60m + 225 + 4N ^ 2 = 3M ^ 2 + 60m + 300 + 3N ^ 2
m^2+n^2=75
So | Z | = √ (m ^ 2 + n ^ 2) = 5 √ 3
z/a+a/z
=(m+ni)/a+a/(m+ni)
=(m+ni)/a+a(m-ni)/(m^2+n^2)
=[(m^2+n^2)(m+ni)+a^2(m-ni)]/a(m^2+n^2)
={[m(m^2+n^2)+a^2m]+[n(m^2+n^2)-a^2n]}/a(m^2+n^2)
Is a real number, the imaginary part is 0
[n(m^2+n^2)-a^2n]/a(m^2+n^2)=0
n(m^2+n^2)-a^2n=0
Z is an imaginary number, and all n are not equal to 0
a^2=m^2+n^2
a=±5√3

The function y = f (x) defined on R satisfies that f (x + 5 / 2) = f (X-5 / 2), (X-5 / 2) f '(x) is greater than 0, and any X1 is less than x2,
What is the condition that f (x1) is greater than f (x2) is (x1 + x2) less than 5?
Let f (x + 5 / 2) = f (5 / 2-x), not f (x + 5 / 2) = f (X-5 / 2)

The condition f (x + 5 / 2) = f (X-5 / 2) shows that it is a periodic function
If (X-5 / 2) f '(x) is greater than 0, it means that he increases from 5 / 2 to positive infinity
Simple subtraction from negative infinity to 5 / 2
How is that possible?
It should be f (x + 5 / 2) = f (5 / 2-x),
This is not a period, it's a symmetric function, about 5 / 2 symmetry, plus conditions
If X-5 / 2) f '(x) is greater than 0, it means that it increases from 5 / 2 to positive infinity
In the negative infinite to 5 / 2 single minus
If f (x 1) is greater than f (x 2), then (x 1 + x 2) is less than 5
If (x 1 + x 2) is less than 5, then f (x 1) is greater than f (x 2)
So it's a necessary and sufficient condition