Why can the branch current and voltage of linear circuit be calculated by superposition principle, but the power can not be calculated by superposition principle?

Why can the branch current and voltage of linear circuit be calculated by superposition principle, but the power can not be calculated by superposition principle?


If the superposition principle can be used for both current and voltage, and S = u * I
So power s can't use superposition principle



When calculating the power of linear resistance circuit, the superposition principle () a is also applicable to B. C can not be used conditionally
Choose B


Power is the product of voltage and current, and current and voltage are linear, so power is not linear and cannot be superimposed



Kirchhoff's law applies to all circuits,


It only applies to lumped parameter circuit. Lumped parameter circuit refers to the circuit whose maximum linear dimension is far less than the wavelength of current or voltage in the circuit, otherwise it is distributed parameter circuit



Five eighths of a ton equals five eighths of a ton equals five eighths of a ton


Exactly
1 × 5 / 8 = 5 × 1 / 8 = 5 / 8 tons



Articles and translation of unit 9 Section B (3a ~ 4)


3a
Yesterday, I asked ten students in No.3 middle school what they did in three weekends. For most children, weekends are happy. On Saturday morning, ten children did their homework and study. On Saturday afternoon, five children went shopping, and three children went to the library. Two children also went to play computer games, Seven children went to the cinema or stayed at home to watch TV. On Sunday, two children visited their friends, nine lost their rooms, and five went to exercise
3b
I had a busy weekend. On Saturday morning, I cleaned my room. In the afternoon, I did my homework. He was a little difficult. On Saturday evening, I visited my aunt. My aunt made dinner for me. On Sunday morning, I went to the library. I read some books about history. In the afternoon, I played football with my friends, I watched TV. I watched an interesting talk show
four
Do you think everyone is enjoying their weekend? Old Henry is not. Last month, he went to the park with his lovely dog, Wang Wang. It was a good day. Old Henry was also very happy. He sat and watched Wang Wang play with a friendly black cat
Then, it's time to go home, but old Henry looks for his dog. But Wang Wang is not here
Old Henry was very sad. He had no dog and no family. He didn't want to do anything more
I wish you progress in your studies and make progress! (*^__ ^*)……



What is the least common multiple of 13 and 36


Because 13 and 36 are coprime, their least common multiple = 13x36 = 468



-On the linear equation of two variables: -)
In the following equation, the one with no solution is ()
A {x+y=1,x-y=1
B {2x-y=3,4x-2y=6
C {x-y=2,2x-2y=6
D {x-3y=-1,y-x=3


c
2x-2y = 4 and 2x-2y = 6



If a is a rational number that is not zero, compare a / 1 with a


If this problem is to fill in, you can use the special value method, that is, set a number of generations to calculate only
Let a be 2,1 / 2



Grandfather raised 100 chickens and ducks. Later, one fifth of the chickens were sold and eight ducks were bought back. At this time, the number of chickens and ducks was exactly the same. How many chickens and ducks were there
Don't say the answer directly, list the formula. It's better not to use the equation


If chicken has x, duck has 100-x
X-1/5X =100-X+8
X=60



Find the value range of a whose value range of function y = (X & # 178; + AX-2) x & # 178; - x + 1 is (- ∞, 2)
The main reason is that I didn't understand the operation process ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~
Solution: let (X & # 178; + AX-2) \ \ X & # 178; - x + 1 < 2, ∵ X & # 178; - x + 1 = (x-1 / 2) &# 178; + 3 / 4 > 0
②∴x²+ax-2<2x²-2x+2
③ This inequality holds for X ∈ R
④ The solution is - 6 < a < 2
⑤ Let the function y = (X & # 178; + AX-2) / X & # 178; - x + 1 be in the range of (- ∞, 2), and the value range of a is {a | - 6 < a < 2}


② To 3 is equivalent to "2 A0 is established"
③ It is because: y = x & # 178; - (a + 3) x + 4, if the opening is upward, there is no intersection with the X axis (B & # 178; - 4ac)