What are the components of a sine wave oscillator

What are the components of a sine wave oscillator

In order to establish oscillation, an oscillator must satisfy two basic conditions of self-excited oscillation. When the amplitude of oscillation increases gradually and finally reaches the steady state, the circuit needs to have a stabilizing link to reduce the amplification factor of the amplifier and meet the amplitude condition of AF = 1

In essence, the sine wave oscillation circuit is a kind of circuit
A positive feedback amplifier satisfying self-excited oscillation condition
B negative feedback amplifier circuit
C positive feedback amplifier only satisfying phase balance condition
D amplifier circuit which only satisfies the condition of amplitude balance

Sine wave oscillator is essentially a feedback amplifier with frequency selective network which satisfies the condition of self-excited oscillation. It consists of three parts: amplifying circuit, positive feedback network and frequency selective network. The key to analyze whether the circuit oscillates is the phase balance condition. If the phase balance condition is not satisfied, it can not oscillate

It is known that the period of a sinusoidal AC voltage is 10 ms, the effective value is 220 V, and when t = 0, it is in the zero value from positive value to negative value（

The period is 10ms, f = 1 / T = 100Hz, angular velocity (i.e. ω = 2 π f), ω = 2F π
When t = 0, the initial angle π is in the zero value of transition from positive value to negative value;
Expression = 220 √ 2Sin (200 π + π)

The phase of sinusoidal quantity indicates the state of sinusoidal quantity at a certain time

Yes, phase, as the name suggests, is the state of the moment, but it cannot be understood as a sine function. The image is its state. It usually represents the microscopic instantaneous state of different microscopic quantities, that is, this "state" is not that "state". Please understand

Given the function f (x) = 1 − m + lnxx, m ∈ R, find the extremum of F (x)

If the definition domain of function is (0, + ∞), then the derivative of function is f ′ (x) = 1 x · x − (1 − m + LNX) x2 = m − LNX 2, from F ′ (x) = m − LNX 2 ＞ 0, that is LNX ＜ M, that is 0 ＜ x ＜ em, then the function increases monotonically, from F ′ (x) = m − LNX 2 ＜ 0, that is LNX ＞ m, that is x ＞ em, then the function recurs monotonically

How many cubic centimeters is the volume of a solid figure obtained by rotating a right triangle around the AC axis?
Is a right triangle, AB length of 4cm, AC length of 5cm, BC length of 3cm, the topic is Rao AC axis rotation a week to get the volume of three-dimensional graphics is how many cubic centimeters, how to ask ah, please help experts, thank you!

The height on the side of AC is 12 / 5
Volume = 1 / 3 * PI (12 / 5) ^ * 5 = 144pi / 15
Note: the stereogram after rotation shows two cones, and the bottom area of the cone is pi (12 / 5)^
The volume of the cone is 1 / 3 * bottom area * height

What is the formula for the total power of a parallel circuit?

Ptotal = P1 + P2 +. PN
P=U(I1=I2+I...+In)

Given the complete set I = {1.2.3.4.5.6} set = {1.2.3.5}, n = {2.4.6. A}, if M ∩ C1 n = {1.5}, then element a=

Complete set I = {1,2,3,4,5,6}
M={1,2,3,5}
N={2,4,6,a}
M∩{CrN}={1,5}
1 ∈ CrN, and 5 ∈ CrN
Both 1 and 5 do not belong to n,
∴a=3.

As shown in the figure, point C is the midpoint of AB, ad = CE, CD = be

In △ ACD and △ CBE, ad = CECD = beac = CB, (5 points) ≌ ACD ≌ CBE (SSS). (6 points)

Given that point a (0, radical 3) and circle O1: x ^ 2 + (y + radical 3) ^ 2 = 16, point m moves on circle O1, point P moves on radius o1m, and | PM = | PA |,
Then the trajectory equation of the moving point P is x ^ 2 / 4 + y ^ 2 = 1, then the minimum distance from the moving point P to the vertex B (- A, 0)

If the trajectory equation of P has been worked out and the minimum distance is obtained, the case of a is discussed
The absolute value of a is less than the root sign 3. In the ellipse, the minimum distance between the two focal points should be the intersection of the vertical line of B and the ellipse (- A, under the root sign (1-A ^ 2 / 4));
The absolute value of a is greater than or equal to the root sign 3 and less than 2. Between the focus of the ellipse and the ellipse, the minimum value is 2 - \ \;
The absolute value of a is equal to 2. On the ellipse, the minimum value is 0;
The absolute value of a is greater than 2. On the outside of the ellipse, the minimum value is - 2
The calculation may not be accurate, but the meaning should be good