What does character ch * 71 mean in FORTRAN

What does character ch * 71 mean in FORTRAN


Ch is defined as a character variable with a length of 71
It can also be written like this: character * 71 ch or character (len = 71) ch



On dimension in VFP
DIMENSION M(2,2)
M(1,1)=10
M(1,2)=20
M(2,1)=30
M(2,2)=40
M(2)
Results


Dimension m (2,2) this command defines a two-dimensional array, which contains four elements. The order is: m (1,1) m (1,2) m (2,1) m (2,2) m (2,2) can be expressed as a one-dimensional component



Given that the solution of the equation MX + 2 = 3 (M-X) about X is - 1, then the value of M is -


Because the solution of the equation MX + 2 = 3 (M-X) about X is - 1
So substituting x = - 1 into the original equation, we get
-m+2=3(m+1)
-m+2=3m+3
-4m=1
m=-1/4



One third x-178; - x-0.5 = 0
Using formula to solve the problem


One third x-178; - x-0.5 = 0
x²-3x-3/2=0
b²-4ac=9+6=15
∴ x=[﹣b±√﹙b²-4ac﹚]/2a
=﹙3±√15﹚/2
x1=﹙3+√15﹚/2
x2=﹙3-√15﹚/2.



Approximate score: 3B & # 178; + a of AB & # 178; + 3AB


A * (a + 3b) of B * (a + 3b) is obtained by putting forward the numerator A and denominator B
When a + 3b is not equal to 0, the original formula is equal to a / b,
When a + 3B = 0, it cannot be reduced



What is the relationship between the linear equation of one variable 0.5x + 1 = 3 and the linear function y = 0.5x + 1


The solution (x, 3) of the equation is a point on a linear function



If the determinant of matrix A of order 4 | a | = - 5, a * is the adjoint matrix of a | a * | =? Answer - 125


a*=|a|*a^(-1)=-5*a^(-1)
|a*|=|-5*a^(-1)|=(-5)^4 *|a^(-1)| ...①
∵a^(-1) *a=E,
|a ^ (- 1) | * |a | = 1, so |a ^ (- 1) | = 1 / |a | = - 1 / 5
(1) formula = (- 5) ^ 4 * (- 1 / 5) = - 125



The general term formula of the sequence [an] is an = [2, (n = 1) [n & # 178;, (n ≥ 2), then the first three terms of the sequence are


an=〔2,(n=1)〔n²,(n≥2)
a1=2
a2=4
a3=9



0.4x+16=0.6x-8


0.4X-0.6X=-8-16
-0.2X=-24
X=120



The minimum value of quadratic function y = (x-1) 2 + 2 is ()
A. -2B. 2C. -1D. 1


∵ (x-1) 2 ≥ 0, ∵ y = (x-1) 2 + 2 ≥ 2, ∵ the minimum value is 2