How to use matlab to find the unknowns in a matrix is to know the product of a known matrix and a matrix containing unknowns and find those unknowns

For example:
A=[1,2,a,3,4];
B=[3;4;2;1;1];
b=3;
Where a is a known matrix, B is a matrix with unknown a, and B is a product,
Matlab code is as follows:
syms a
A=[1,2,a,3,4];
B=[3;4;2;1;1];
b=3;
f=A*B-3;
g=solve(f,a)
Other matrices can be done in a similar way

Matlab row vector multiplication matrix
The following matrix is generated with the statement of multiplication of row vectors
1 1 1 1 1
1 2 4 8 16
1 3 9 27 81
1 4 16 64 256

>> a=[1 1 1 1 1;2 2 2 2 2;3 3 3 3 3;4 4 4 4 4]a =1 1 1 1 12 2 2 2 23 3 3 3 34 4 4 4 4>> b=[0 1 2 3 4;0 1 2 3 4;0 1 2 3 4;0 1 2 3 4]b =0 1 2 3 40 1 2 3 40 1 2 3 40 1 2 3 4>> a.^bans =1 1 1 1 11 2 4 8 1...

Multiplication of two matrices requires I to be constant and j to be variable
a=[839 817 87 897 734 74 758 15 80.5
775 813 86 887 723 91 763 15 73.0
824 835 82 855 689 92 726 10 68.0
777 810 89 840 658 88 748 0 75.0
790 795 84 791 672 75 692 20 60.0
707 730 108 842 667 73 738 0 55.5
792 754 87 767 632 74 687 0 74.5
776 779 102 788 600 82 632 15 45.0
753 712 94 767 640 75 710 10 49.0
662 751 80 780 667 70 717 0 78.5
695 809 82 767 604 79 689 10 75.0
744 723 86 766 652 74 674 0 61.5
728 748 92 775 636 78 648 0 70.0
660 706 94 808 639 91 700 0 50.5
763 710 92 759 587 69 713 0 65.0
654 740 80 771 618 70 711 0 78.0
592 738 88 769 659 75 690 5 51.5
646 742 91 768 560 79 651 0 51.5
653 682 93 766 600 70 659 5 50.5
700 662 92 731 582 75 628 0 43.5
601 686 78 773 578 70 653 5 54.5
565 747 81 743 569 67 636 10 72.0
469 619 79 722 581 68 695 0 50.5
451 686 79 681 558 67 596 0 61.5
427 657 78 657 466 68 660 0 54.0
436 565 80 520 262 68 496 0 60.0
0 199 80 458 417 68 627 0 30.5];
b=[0.1541 0.1664 0.0606 0.1142 0.1251 0.0777 0.1235 0.0685 0.1098];

>> a*b'
ans =
five hundred and seventy-four point zero zero zero nine
five hundred and sixty-two point zero zero nine one
five hundred and fifty-nine point six eight seven three
five hundred and forty-five point six zero seven five
five hundred and thirty-two point seven six four three
five hundred and nineteen point four seven two six
five hundred and eighteen point two one four zero
five hundred and ten point eight two nine nine
five hundred and seven point four four three six
five hundred and six point nine five four one
five hundred and nine point nine eight seven nine
five hundred and four point nine five three one
five hundred and four point zero seven zero four
four hundred and ninety-six point one five eight nine
five hundred and one point nine six two eight
four hundred and ninety-five point nine three seven three
four hundred and eighty-six point six six three six
four hundred and seventy-eight point four eight five one
four hundred and seventy-four point nine nine eight zero
four hundred and sixty-eight point zero five two two
four hundred and sixty-four point four eight six eight
four hundred and sixty-four point six five zero nine
four hundred and thirty-one point eight five eight four
four hundred and twenty-one point five seven seven five
four hundred and five point nine zero one one
three hundred and thirty-one point three three nine four
two hundred and twenty-eight point four nine eight nine
>>

In quadratic function, X1 + x2 =?, x1. X2 =?

x1+x2=-b/a
x1*x2=c/a

The increasing intervals of functions f (x) = | x | and G (x) = x (2-x) are______ ．

F (x) = | x | = x, X ≥ 0 − x, x < 0, that is, the monotone increasing interval of the function is [0, + ∞]. G (x) = x (2-x) = 2x-x2 = - (x-1) 2 + 1, the axis of symmetry is x = 1, the parabola opening is downward, the monotone increasing interval of 〈 g (x) is, (- ∞, 1], so the answer is: [0, + ∞), (- ∞, 1]

If the function f (x) defined on R satisfies f (x) f (x + 3) = 13, if f (3) = 2, then f (2010)

f(x)f(x+3)=13
f(x+3)f(x+6)=13
So f (x) = f (x + 6)
So f (6) = f (12) =... = f (2010)
And f (6) = 13 / F (3) = 13 / 2
So f (2010) = f (6) = 13 / 2

When a is less than 0, what is the absolute value of 1 minus 2A

When a is less than 0, the absolute value of 1 minus 2a is equal to 1-2a

How to distinguish imperative sentences from gerund phrases

The beginning of imperative sentence is verb prototype
A gerund phrase begins with a present participle

ABCD = 1 find 1 + A + AB + ABC 1 + 1 + B + BC + BCD 1 + 1 + D + CD + CDA 1 + 1 + D + Da + DAB 1

1+a+ab+abc = abcd+a+ab+abc
= a（bcd+1+b+bc）=a（bcd+abcd+b+bc）
= ab（cd+acd+1+c）=ab（cd+acd+abcd+c）
= abc（d+ad+abd+1）
So the original formula = 1 / (1 + A + AB + ABC) * (1 + A + AB + ABC)
=1
Note: your title is wrong. 1 + D + CD + CDA should be 1 + C + CD + CDA

A number of can only describe the plural of countable nouns?

A number of can only describe the plural of countable nouns
Many, many, many
eg.A number of students walk to school.
Some (many) students go to school on foot

How to use matlab to find the unknowns in a matrix is to know the product of a known matrix and a matrix containing unknowns and find those unknowns