lg10+lg6/lg3=?

lg10+lg6/lg3=?

1+log2

What is LG6 minus Lg3,

lg6-lg3=lg(6÷3)=lg2

If 6 ^ a = 5, then | G25 / LG6 is equal to?

6 ^ a = 5, a = log (6,5) (6 is base, 5 is true) LG25 / LG6 = log (6,25) = log (6,5) = 2log (6,5) = 2A

Given Lg3 / LG10 = a, LG25 / LG6 = B, find LG45 / LG4
RTRT

It depends on the conditions
2lg5/(lg2+lg3)=b
lg3/(lg2+lg5)=a
As a system of equations about Lg3 and lg5, the solution containing LG2 is obtained. The solution can be obtained by taking (lg5 + 2lg3) / 2lg2 and eliminating LG2
If I'm right, it should be (4a + 3AB + b) / 2 (2-AB)

When using the method of undetermined coefficients to solve the differential equation y '' - 2Y '+ y = 2xe ^ 2x - (SiNx) ^ 2, what is the form of the special solution
thank you.

The solution of 2xexp (2x) + (SiNx) ^ 2 = 2xexp (2x) + 1 / 2 - (cos2x) / 2Y '' - 2Y '+ y = 0 is y = (C1 + c2x) exp (x) structure, which is different from 2xexp (2x) and (SiNx) ^ 2 = (1-cos2x) / 2. For 2xexp (2x), let the special solution Y1 = (AX + b) exp (2x) Y1' '- 2y1' + Y1 = (AX + B + 2a) exp (2x) = 2xexp (2x) get a = 2

It is known that there are six integer solutions of the inequality system x-a > 2,3-2x > 0 about X, then the value range of a is

From the meaning of the title
a+2

Find 200 oral arithmetic questions and 100 vertical arithmetic questions in Volume 1 of grade 4
The best is the mathematics published by Jiangsu Education Press

2.8×0.4＝ 1.12
14－7.4＝6.6,
1.92÷0.04＝48,
0.32×500＝160,
0.65＋4.35＝ 5
10－5.4＝4.6,
4÷20＝0.2,
3.5×200＝700,
1.5－0.06＝1.44
0.75÷15＝0.05,
0.4×0.8＝0.32,
4×0.25＝1,
0.36＋1.54＝2
1.01×99＝99.99,
420÷35＝12,
25×12＝300,
135÷0.5＝270
3/4 + 1/4 =1,
2 + 4/9 =22/9,
3 - 2/3 =7/3,
3/4 - 1/2= 1/4
1/6 + 1/2 -1/6 =1/2,
7.5-(2.5+3.8)=1.2,
7/8 + 3/8 =5/4
3/10 +1/5 =1/2,
4/5 - 7/10 =1/10,
2 - 1/6 -1/3 =1.5
0.51÷17＝0.03,
32.8＋19＝51.8,
5.2÷1.3＝4,
1.6×0.4＝ 0.64
4.9×0.7＝3.43,
1÷5＝0.2,
6÷12＝0.5,
0.87－0.49＝0.38
1.(1+1/2)(1+1/3)(1+1/4).(1+1/100)
2.(1-1/2)(1-1/3)(1-1/4).(1-1/100)
3.8+2-8+2
4.25*4/25*4
5.7.26-(5.26-1.5)
6.286+198
7.314-202
8.526+301
9.223-99
10.6.25+3.85-2.125+3.875
11.9-2456*21
12.0.5/11.5-4*2.75
13.1/2×3/5
14.3.375+5.75+2.25+6.625
15.1001－9036÷18
16.3.8×5.25+14.5
17.2.1*4.3+5.7*2.1
18.30×1/3
19.102*45-328
20.2/3×12
21.2.8*3.1+17.6/8
22.3/5×5/6
23.(50-12.5)/2.5
24.2/5×1/3
25.6110*47+639
26.1/2-1/6
27.3.5*2.7-52.2/18
28.1/7×1/5
29.3.375*0.97+0.97*6.625
30.25×4/5
31.6.54+2.4+3.46+0.6
32.5/6-1/2
33.95.6*1.8+95.6*8.2
34.1/2×1/5
35.600-420/12
36.344/3.6-5.4*0.25
37.16/2+30/2+90/6
38.3001-1998.
39.5000-105*34
40.0.15/0.25+0.75*1.2
41.(1/2+1/3+1/4)*0.24
42.(25+4)*4
43.300-4263/21
44.0.81/0.25+5.96
45.403÷13×27
46.1.5×4.2－0.75÷0.25
47.3.27×4 +3.27×5.7
48.（1.2+ 1.8）×4.51025－768÷32
49.0.25×80－0.45÷0.9
50.1025－768÷32
51.0.25*2.69*4
52.2348+275*16
53.2/9*15/8-1/12*9/5
54.2.4+2.4*(5.375-3.375)
55.645-45*12
56.0.15+1.2/0.24-0.45
57.3.75-(2.35+0.25/1.25)
58.76*1/4+23*25/100+0.25
59.10-2.87-7.13
60.0.96+9.6*9.9
61.7.5-5.7*1/3
62.12.37-3.25-6.75
63.16*6.8+2.2*16+16
64.401*19+284
65.58.7-16.65/3.7
66.0.4*4.7*2.5+(2.3+5.3)
67.9.31-1.125-7.875
68.640+128*45
69.8.2*1.6-0.336/4.2
70.400*(0.62+0.08)
2/1*2=1
3/1*3=1
3/2*3=2
3/1*6=2
4/3*8=6
5/3*20=12
7/3*14=6
8/7*40=35
4/3*16=12
9/5*27=15
2/1*30=15
12/7*24=14
30/1*30=1
51/9*102=18
19/9*76=36
4/9*8=18
5/8*90=144
99/98*99=98
3/14*6=28
7/1*28=4
10/1*90=9
5/3*105=63
19/7*38=14
5/1*25=5
8/19*16=38
61/60*122=120
7/2*28=8 6/1*48=8
9/7*18=14
25/7*100=28
9/5*81=45
8/9*16=18
2/1*2=1
3/1*3=1
3/2*3=2
3/1*6=2
4/3*8=6
5/3*20=12
7/3*14=6
8/7*40=35
4/3*16=12
9/5*27=15
2/1*30=15
12/7*24=14
30/1*30=1
51/9*102=18
19/9*76=36
4/9*8=18
5/8*90=144
99/98*99=98
3/14*6=28
7/1*28=4
10/1*90=9
5/3*105=63
19/7*38=14
5/1*25=5
8/19*16=38
61/60*122=120
7/2*28=8
6/1*48=8
9/7*18=14
25/7*100=28
9/5*81=45
8/9*16=18
12÷3/5=12×(5/3）
9÷6/7=9×( 7/6 )
30÷5/6=30×（6/5 ）
4×（3/2 ）=4÷2/3
4÷5/7=4×7/5
3÷4/5=3×5/4
24÷7/16=24×（16/7 ）
A÷C/B=A×B/C
4÷4/5=5
6÷3/4=8
10÷2/5=25
18÷4/9=81/2
4×4/5=16/5
6×3/4=18/4
10×2/5=4
18×4/9=8
3÷3/4=4
2÷1/3=6
6÷4/5=15/2
1÷5/7=7/5
3/4÷3=1/4
1/3÷2=1/6
4/5÷6=2/15
5/7÷1=5/7
2/1*2=1
3/1*3=1
3/2*3=2
3/1*6=2
4/3*8=6
5/3*20=12
7/3*14=6
8/7*40=35
4/3*16=12
9/5*27=15
2/1*30=15
12/7*24=14
30/1*30=1
51/9*102=18
19/9*76=36
4/9*8=18
5/8*90=144
99/98*99=98
3/14*6=28
7/1*28=4
10/1*90=9
5/3*105=63
19/7*38=14
5/1*25=5
8/19*16=38
61/60*122=120
7/2*28=8
6/1*48=8
9/7*18=14
25/7*100=28
9/5*81=45
8/9*16=18

Positive sequence A0, A1, A2. An... Satisfies √ ana (n-2) - √ a (n-1) a (n-2) = 2A (n-1) (n ≥ 2), and A0 = A1 = 1, find the general term

If both sides of the original formula are divided by a (n-1) to get √ [ana (n-2) / a (n-1) ^ 2] - √ [a (n-2) / a (n-1)] = 2, let BN = √ [an / a (n-1)], then B1 = √ (A1 / A0) = 1, so BN / b (n-1) - 1 / b (n-1) = 2, that is, BN = 2B (n-1) + 1 (n ≥ 2), so BN + 1 = 2 [b (n-1) + 1], B1 + 1 = 2, so {BN + 1} is the first term of 2, and the common ratio is 2

1 / 4x-1 / 2 = 3 / 4 and 7x-5 / 4 = 3 / 8
1 / 4x-1 / 2 = 3 / 4 and 7x-5 / 4 = 3 / 8 I have nothing to share with you

1/4x-1/2=3/4 1/4x=1/2+3/4 1/4x=5/4 X=5 7x-5/4=3/8 7x=5/4+3/8 7x=13/8 X=13/56

A barrel of oil weighs 20 kg. When it is poured out of 13, it weighs 14 kg______ Kilogram

20 - (20-14) △ 13 = 20-6 △ 13 = 20-18 = 2 (kg); answer: the barrel weighs 2kg