The domain of function f (2 ^ x) is [- 1,1], find the domain of F (log2x)

The domain of function f (2 ^ x) is [- 1,1], find the domain of F (log2x)

∵x∈[-1,1]
∴2^x∈[1/2,2]
The domain of definition f (x) is [1 / 2,2]
1/2≤log2x≤2
log2(√2)≤log2x≤log2(4)
√2≤x≤4
The definition field of y = f (log2x) is [√ 2,4]

Find the definition field of function y = √ (in (x + 1)) / (- x ^ 2-3x + 4)
The answer is that x belongs to the process of [0,1] solving a complete problem

Is the whole formula under the root?
There are two possibilities for a domain:
1）ln(x+1)>=0--> x+1>=1--> x>=0
-x^2-3x+4>0--> x^2+3x-4 (x+4)(x-1) -4

1. The domain of the function y = in (3x-2) is?
2. The tangent equation of the curve y = cos at the point (π / 3,1 / 2) is?
3. The law of arrangement of an object s (T) = 3t-t & # 178; when moving in a straight line, the velocity (3 / 2) =?
What is the approximate value of in1.02?
5. If f (x) = ax & # 178; + BX has the maximum value 2 at point x = 1, then a =?
6. The monotone increasing interval of function f (x) = 2 / 3 of X is?

1: The derivative of the curve y = COS is y = - sin, so the slope of the tangent equation is - √ 3 / 2, and the equation is y = (- √ 3 / 2) x + √ 3 π / 6 + 0.53: I don't know what the annihilation law is, but I can do it according to the knowledge of physics

Proof: the equation (x power of 2-1) / (x power of 2 + 1) = LNX has at least one root in the interval (1,3)

Let f (x) = (2 ^ x-1) / (2 ^ x + 1) - LNX, then f (1) = 1 / 3 > 0, f (3) = 7 / 9-ln3

What's the surprise English word?

Surprise

If S2 = 2, S4 = 10, then S6 equals ()
A. 12B. 18C. 24D. 42

The sum of the first n terms of ∵ arithmetic sequence {an} is SN. S2, s4-s2 and s6-s4 form arithmetic sequence, that is, 2, 8 and s6-10 form arithmetic sequence, 2 + s6-10 = 8 × 2 and S6 = 24, so C is selected

Let z = XY ^ 3-x ^ 2Y ^ 6, then the total differential DZ of point (1,1) is=

z'x=y^3-2xy^6
z'y=3xy^2-6x^2y^5
x=1,y=1
z'x=-1
z'y=-3
dz=-dx-3dy

How to simplify the operation of 11 times 11 times 11 minus 11 times 11

11*11*11-11*11
Original formula = 11 * 11 (11-1)
=11*11*10
=10*（11*11）
=10*121
=1210

The volume formula of a circle is 20 meters in diameter and 4 meters in height

20 / 2 = 10 (radius)
Half the diameter is the radius
10 * 10 * 3.14 = 314 (bottom area)
The square of the radius multiplied by the ratio of states = area
314 * 4 = 1256 m ^ 3 (cylinder volume)
Bottom area times height = volume

How do you remember the Taylor formula of commonly used functions? Is there any memory method that you always forget
Let's learn from each other

General Taylor formula, to their own derivation. Recursive formula to remember, it is best to quickly write the first four, the speed of the problem will improve very quickly