If log (a) x = 2, log (b) x = 3, log (c) x = 6, then log (ABC) x =? Is the base number in brackets

If log (a) x = 2, log (b) x = 3, log (c) x = 6, then log (ABC) x =? Is the base number in brackets

The answer is 1
From the meaning of the title: x = a ^ 2
x=b^3
x=c^6
So ABC = x ^ (1 / 2 + 1 / 3 + 1 / 6) = X
So log (ABC) x = log (x) x = 1

If a + B = 0, ab = - 5, then a square, B + AB square =, a square + b square=

a+b=0
ab=-5
A square B + AB square = = AB (a + b) = AB * 0 = 0
A square + b square = (a + b) ^ 2-2ab = 0-2 * (- 5) = 10

A + B = 0, ab = 1, find the square of a - the square of AB + B

a^2-ab+b^2
=a^2+2ab+b^2-3ab
=(a+b)^2-3ab
=0-3
=-3

We know the following group of numbers: 1,3 / 4,5 / 9,7 / 16,9 / 25... And express the nth number with algebraic expression
Can you write in more detail? It's better to have a written explanation! Because I'm not seeking answers, but learning knowledge,
Why is "an =..." not n?

Focus on observation
The first item A1 = (1 * 2-1) / 1 ^ 2
The second A2 = (2 * 2-1) / 2 ^ 2
The third A3 = (3 * 2-1) / 3 ^ 2
……
The nth term an = (2n-1) / N ^ 2
An is the nth number, and N is the nth item

How many zeros are there at the end of the product of 1 times 2 times 3 times 4. Times 200?

1. There are 20 zeros, of which 50100150200 are not included for the time being. Because of their special situation, there are 16 zeros left
2.50150 times an even number can get two 0100200, and there are two zeros in itself, which is eight
3. The number of bits with 5, of which 25, 75125175 are not included for the time being, and the rest are 16. They multiply by an even number to get 1 0, which is 16
4.25, 75175 times a multiple of 4 will get 2 zeros, which is 8 zeros
5.125 times 8, that's three zeros
So to sum up, there are 49 zeros

The three sides of the triangle are 5, 6 and 9 respectively, and the area of the triangle is calculated

If you have Helen's formula, half perimeter = (5 + 6 + 9) / 2 = 10s = √ 10 * (10-5) (10-6) (10-9) = √ 10 * 5 * 4 * 1 = √ 200 = 10 √ 2, otherwise you can only use cosine theorem first, and then sine theorem 6 & # 178; = 5 & # 178; + 9 & # 178; - 2 * 5 * 9cosx36 = 106-90cosx to get cosx = 7 / 9, then SiNx = √ 1 & # 178; - (7 / 9) & #

To solve the equation x-3 / 8-1 / 8 = 11 / 18

X - 3 / 8 - 1 / 8 = 11 / 18
X - (3 / 8 + 1 / 8) = 11 / 18
X-half = 11 / 18
X-half + Half = 11 / 18 + 9 / 18
X = 20 out of 18 reduced to 1 and 1 out of 9

The diameter of a semicircle is 2 decimeters, and its circumference is______ The area is______ ．

3.14 × 2 △ 2 + 2, = 3.14 + 2, = 5.14 (decimeter); 3.14 × (22) 2 △ 2, = 3.14 × 1 △ 2, = 1.57 (square decimeter). Answer: perimeter is 5.14 decimeter, area is 1.57 square decimeter. So the answer is: 5.14 decimeter; 1.57 square decimeter

Simple operation of primary school mathematics 4.8 × 7.8 + 78 × 0.52

Method 1: = 4.8 × 7.8 + 7.8 × 5.2
=(4.8＋5.2)×7.8
= 10 ×7.8
=78
Method 2: = 0.48 × 78 + 78 × 0.52
=(0.48＋0.52)×78
= 1×78
=78

As shown in the figure, it is known that ad = BC, ab = DC, de = BF. Question: is be equal to DF? And why?

It is proved that: ∵ ad = BC, ab = DC, ∵ quadrilateral ABCD is parallelogram, ∵ ad ∥ BC is de ∥ BF, ∵ de = BF, ∵ quadrilateral debf is parallelogram, ∵ be = DF