On the quadratic equation of one variable of X, there are two real solutions of 3K-1 X-1 = 0 under KX root

On the quadratic equation of one variable of X, there are two real solutions of 3K-1 X-1 = 0 under KX root

There are two real number solutions for △ = (- √ 3K-1) ^ 2-4 × K × (- 1) = 3K-1 + 4K = 7k-1, 3K-1 X-1 = 0 under ∵ KX square root, that is, 7k-1 ≥ 0, K ≥ 1 / 7, K ≥ 1 / 7

Which number is the square of 15 plus the square of 20?
I know the answer, I want to know the steps, detailed, urgent, thank you

15^2+20^2
=225+400
=625
25 square

Solving equation [(x + 0.6) + x] * 9 = (10 + 3) * (x + 0.6) + 3x

[(x+0.6)+x]*9=(10+3)*(x+0.6)+3x
（2X+0.6）*9=13X+7.8+3X=16X+7.8
18X+5.4=16X+7.8
18X-16X=7.8-5.4=2.4
2X=2.4
X=1.2

Given the proposition p: "for any x ∈ [1,2], x2-a ≥ 0", proposition q: "there exists x ∈ R, X2 + 2aX + 2-A = 0". If the proposition "P and Q" is true, the value range of real number a is obtained

"For any x ∈ [1,2], x2-a ≥ 0". Then a ≤ X2, ∵ 1 ≤ x2 ≤ 4, ∵ a ≤ 1, that is, when the problem P is true: a ≤ 1. If "there exists x ∈ R, X2 + 2aX + 2-A = 0", then △ = 4a2-4 (2-A) ≥ 0, that is, A2 + A-2 ≥ 0, the solution is a ≥ 1 or a ≤ - 2, that is, when the proposition q is true: a ≥ 1 or a ≤ - 2. If "P ∧ Q" is a true proposition, then p and Q are both true propositions, that is, a ≤ 1a ≥ 1 or a ≤ - 2, the solution is a = 1 The range of real number a is a = 1 or a ≤ - 2

Minus 39 and 23 / 26 divided by 1 / 13

(- 39 and 23 / 26) △ 1 / 13
=(- 39 and 23 / 26) * 13
=-39*13-23/26*13
=-507-23/2
=-518 and 1 / 2

Let the line I pass through the point (0, - 2) and be tangent to the circle x2 + y2 = 1, then what is the slope of I?
X2 + Y2 is the square of X + the square of Y

I don't know if you've ever learned derivative. If you've learned derivative of a circle, you can do it directly. If you haven't learned derivative, let's set a point (x0, Y0) on the circle. Then the line passing through (0, - 2) and (x0, Y0) is tangent to the circle, that is, the distance from the center of the circle to the line is equal to 1

English words from 1 to 100
It's Microsoft's hair loss

1one 2 two 3 three 4 four 5 five 6 six 7 seven 8 eight 9 nine 10 ten 11 eleven 12 twelve 13 thirteen 14 fourteen 15 fifteen 16 sixteen 17 seventeen 18 eighteen 19 ninetee 20 twenty 21 twenty-one 22 tw...

LNX expands into (x-x0) power series at x0 = 2

Using 1 / (1 + x) = 1-x + x ^ 2-x ^ 3 +. (- 1)

What is 1 plus 980 times 56 divided by 7?

1+980×56÷7=7841
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If the function y = - x square - 4mx + 1 is a decreasing function on [2, + ∞), then the value range of M is
On [1,2], the maximum value of the function f (x) = a to the power of X (a > 0 and a is not equal to 1) is a / 2 larger than the minimum value,
The value of a is

1. The function is a quadratic function, and the opening of the image is downward. It is easy to find that the axis of symmetry is x = 2m. Because the function increases monotonically on the left side of the axis of symmetry and decreases monotonically on the right side of the axis of symmetry, it is necessary to reduce the function to 2m in [2, + infinity]