Finding the integer solution of the equation x & # 178; - XY + Y & # 178; - 2x-2y + 3 = 0

Finding the integer solution of the equation x & # 178; - XY + Y & # 178; - 2x-2y + 3 = 0

The answer to this question is x = 1, y = 1

Find the integer solution of the following equation: ① xy-2x-2y + 7 = 0; ② A & sup2; + ab-2b & sup2; = 13
Urgent,

① Xy-2x-2y + 7 = 0; (X-2) (Y-2) = - 3x-2 = - 1, Y-2 = 3; or X-2 = 1, Y-2 = - 3; or X-2 = - 3, Y-2 = 1; or X-2 = 3, Y-2 = - 1, y = 5; or x = 3, y = - 1, y = 3; or x = 5, y = 1, ② A & sup2; + ab-2b & sup2; = 13 (a + 2b) (a-b) = 13A + 2B = 1, or a + 2B = 13; or a + 2B = - 1

11. The integer solution of the equation xy-2x-2y + 7 = 0 is________ .

x=1,y=5;
x=5,y=1;
x=-1,y=3;
x=3,y=-1;

Find the positive integer solution of equation x's Square - Y's Square = 8

X^2 - Y^2
= (X + Y)(X - Y) = 8 = 2×2×2
It is easy to know that x > y, x + Y > x - y, and
The parity of X + y and X - y is the same, because x + y and X - y cannot be odd (product = 8)
Therefore, there are only:
X + Y = 4
X - Y = 2
Solution
X = 3
Y = 1

Solving the equation: x minus two thirds x equals two ninths, three fourths minus two x equals five eighths, please use words instead, thank you

First: one third x = two ninths x three ninths x = two ninths x x = one nineth second answer: - 2x = five eighths minus three fourths - 2x = five eighths minus six eighths - 2x = one eighth x = two eighths x = one and two eighths x = one fourth

A semicircle has a diameter of 4 decimeters. What are its perimeter and area?

Area = 12.56 square decimeters perimeter = 12.56 decimeters

How to calculate 52.5 * 0.63 + 3.7 * 5.25

52.5*0.63+3.7*5.25
=52.5*0.63+0.37*52.5
=52.5*(0.63+0.37)
=52.5*1
=52.5

We know AB = DC, ad = BC, de = BF. Prove be = DF
It's done with congruent triangles

Proof: connect AC and DB
In △ ADC and △ ABC
AD=BC,AB=DC,AC=CA
So △ ADC ≌ ABC
Therefore, DAC = ACB
So ad ‖ BC
Therefore, EDB = DBF
And because de = BF, DB = dB
So △ DEB ≌ △ DBF
So be = DF

If vector groups B1, B2 and B3 are expressed linearly by vector groups A1, A2 and A3, B1 = a1-a2 + a3, B2 = a1 + A2-A3, B3 = - a1 + A2 + a3
Let vector group a1.a2.a3 be represented by vector group b1.b2.b3,

(b1,b2,b3)=(a1,a2,a3)K
K=
1 1 1
-1 1 1
1 -1 1
Find the inverse of K, that is, (A1, A2, A3) = (B1, B2, B3) k ^ - 1
Because K ^ - 1=
1/2 -1/2 0
1/2 0 -1/2
0 1/2 1/2
So A1 = (1 / 2) (B1 + B2)
a2 = (1/2)(-b1+b3)
a3 = (1/2)(-b2+b3)

For a trapezoidal piece of paper, the bottom is 24cm, the top is 18cm, and the height is 14cm. Cut it into a triangular piece of paper as large as possible, and calculate the total area of the remaining scraps

24 × 14 △ 2 = 24 × 7 = 168 (square centimeter) a: the total area of the remaining scraps is 168 square centimeter