How to find the definition field of this logarithmic function? It is known that the range of y = LG (2x-3) (3x-5) is r, then the range of its definition is? Please write a detailed explanation! Thank you very much! I know that the true number should be greater than 0, but the Da Er TA of the function of the true number is greater than 0. I don't understand this point!! I want to find the range of X through Da e TA I'm sorry, I don't quite understand. Could you explain it more vividly

The true number is greater than 0
So (2x-3) (3x-5) > 0
x5/3
So the domain of definition (- ∞, 3 / 2) ∪ (5 / 3, + ∞)
The range is r
So we need to get all the positive numbers
That is, the minimum value should be less than or equal to 0
Otherwise, the positive number between 0 and the minimum value cannot be obtained
The real number is a quadratic function with an opening upward
The minimum value is less than or equal to 0
So the discriminant is greater than or equal to 0
It's consistent here, so its range is r

Is y = loga [(x + 1) / (x-1)] a logarithmic function

It's not a logarithmic function, y = loga (x). That's a logarithmic function
f（x）+f（-x）=0
It is shown that this function is only an odd function, but it can never be regarded as a logarithmic function. However, when [(x + 1) / (x-1)] is regarded as a whole T, the function is a logarithmic function with respect to t, but not a logarithmic function with respect to X

Is the function y = loga (x) - n of x a logarithmic function? What about y = loga (x-n)? (a > 0 and a ≠ 1)

The expression of solving logarithm function is y = loga (x) (a > 0 and a ≠ 1)
We know that the function y = loga (x) - n of X is not a logarithmic function, and y = loga (x-n) is not a logarithmic function

If 0 ＜ a ＜ B ＜ 1, a + B = 1, compare a, B, (a + b) &# 178;, the size relation of half is

0 ＜ a ＜ B ＜ 1, a + B = 1, then a ＜ 1 / 2 ＜ B ＜, (a + b) &;

What is the resistivity of the aluminum core

The resistivity of aluminum is 0.028. You can use Ohm's law
Can it solve your problem?

Please write a formula for 1 - 23 - 45 - 67 - 8

n*(-1)^(n-1)

A constant value resistor, the voltage applied to its two ends is 4V, and the current passing through it is 0.5A. What is its resistance value?

According to Ohm's law, r = u / I, r = 4 / 0.5 = 8 Ω

The fourth power of X is - 7x & # 179; - 34x & # 178; + 28x = - 120

x^4-34x²+120-7x（x²-4）=0
（x²-30）（x²-4）-7x（x²-4）=0
（x²-30-7x）（x²-4）=0
（x-10）（x+3）（x+2）（x-2）=0
x1=10,x2=-3,x3=-2,x4=2

In the experiment of small bulb resistance with rated voltage of 3.8V, the equipment prepared by the teacher includes 9V student power supply, an ammeter, a voltmeter, a switch, two sliding rheostats, R1 "10 Ω 1A" R2 "20 Ω 1A", and several wires [the resistance of small bulb normal luminous type is about 8 Ω]
4. Another group also used the above equipment to measure the resistance of the small light bulb, but found that the ammeter could not be used in the experiment. When there was only one voltmeter, the teacher gave them a constant resistance R0. They used the existing equipment to complete the experiment. Please draw the circuit diagram of their experiment in the box, Write a brief experimental procedure and expression

I can't pass the picture, so I'll write out the experiment steps of 4. Please imagine
First, connect the R0, the small bulb and the rheostat in series and connect them to the poles of the power supply. Then adjust the slip rheostat to make the small bulb shine normally. Then use the voltmeter to measure the voltage between the two ends of the R0 U1.
Then calculate the resistance R = R0 × U2 / U1
Do not understand, please ask, feel good, please choose as a satisfactory answer, for the team, thank you

The square of x minus 8x equals 20. How can this equation be solved!

x²-8x=20
x²-8x-20=0
(x + 2) (X-10) = 0 (cross decomposition method)
X = - 2 or x = 10