The domain of the function y = 1 / LG (1-2sinx) is

The domain of the function y = 1 / LG (1-2sinx) is


(1-2sinx) > 0 and not equal to 1,2sinx



What is the domain of the function y = √ (2sinx - √ 3)


That is, 2sinx - √ 3 > = 0
sinx>=√3/2=sin(2kπ+π/3)=sin(2kπ+2π/3)
So 2K π + π / 3



To find the minimum value of the function y = (x ^ 2 + 8) / X-1 (x > 1), use the mean inequality


y=(x^2+8)/x-1
=[(x-1)^2+2x-1+8]/(x-1)
=[(x-1)^2+2x-2+9]/(x-1)
=(x-1)+9/(x-1)+2
>=2*√[(x-1)*9/(x-1)]+2
=6+2
=8
therefore
Minimum = 8



The distance between a and B is 40 km, the speed of motorcycle is 45 km / h, and the speed of freight car is 35 km / h. If there is a batch of goods, the motorcycle can transport it ten times, and the freight car can transport it five times, which car is the fastest? Why? (use the equation to answer)


Why use the equation to solve such a simple problem? It takes time to transport by motorcycle: (40 x 19) / 45 = 152 / 9, by car: (40 x 9) / 35 = 72 / 7, nearly 17 hours for motorcycle and more than 10 hours for car



Given the equations a-2b + 3C = O, 2A + 3b-8c = 0, and ABC is not equal to 0, then the value of a: B: C is


a-2b+3c=o,(1)
2a+3b-8c=0 (2)
(2)-(1)*2:
7b=14c
b=2c
A = 2b-3c = 2 * 2c-3c = C
a:b:c=c:2c:c=1:2:1



Car a and car B travel from a and B at the same time. Car a travels 60 kilometers per hour, and car B travels 50 kilometers per hour. The two cars are 40 kilometers away from the midpoint
How many kilometers are there between a and B?


The two cars met 40 kilometers from the midpoint,
It shows that car a travels 40 + 40 km more than car B when they meet
We also know that car a travels 60-50 kilometers more per hour than car B
So when they met, they went for 80 / 10 = 8 hours
So the distance between a and B is (60 + 50) × 8 = 110 × 8 = 880km
The comprehensive formula is (40 + 40) / (60-50) × (60 + 50) = 880km



If the solution of the equation (1 + 2x) + 3 (x + 1) = 1-2 (2x-1) is the same as that of the equation 2x-3 (2x-m) = 2m-6x, the value of M is obtained


M = 6, the first equation unifies the denominator to take 6 as the denominator, reduces the denominator, may obtain 10x = 6, the second equation unifies the denominator to 3, about simplifies, finally obtains M = 10x
So m = 6
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The speed of a car is 47 times that of a train. Two cars are running from two places at the same time, and they meet at a distance of 15 kilometers from the midpoint. How many kilometers does the train travel?


The distance of the whole journey: 15 △ 74 + 7-12, = 15 △ 322, = 110 (km), the distance of the train: 110 × 711 = 70 (km). A: at this time, the train runs 70 km



The denominator is not 101001000. The fraction can be converted into a decimal by ()


1. Using the basic properties of fraction, it is transformed into 10.100.1000
2. If the division of fractions is not complete, the resulting number shall be 2 as a decimal



Party A and Party B drive from A. Party A goes first. Half an hour later, they chase Party A at a speed of 80 km / h. if they catch up with Party A after 3.5 hours of driving,


"Li Xiaolei 2008":
Let a's speed be x km / h, and the equation is as follows:
(3.5 + 0.5) x = 80 km × 3.5
4x=280
X = 70 km
The speed of a is 70 kilometers per hour
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