Given the function f (x) = (cosx) ^ 2-2asinx (0 ≤ x ≤ π), find the maximum value of F (x)

Given the function f (x) = (cosx) ^ 2-2asinx (0 ≤ x ≤ π), find the maximum value of F (x)

Let t = SiNx
The range of SiNx in 0 ≤ x ≤ π is 0 ≤ SiNx ≤ 1, that is, 0 ≤ t ≤ 1
f(x)=cosx²-2asinx
=1-t²-2at (0≤t≤1)
The function is a function with the opening upward and passing through (0,1)
In four cases, we discuss that the axis of symmetry is on the left side of 0, between 0 and 1 (closer to 0 and closer to 1) and on the right side of 1
The axis of symmetry is t = - A
1. When a > = 0
f(1)min=-2a
f(0)max=1
2.-1/2=

Function y = {2x, O}

#include
int main(int argc,char *argv[])
{
int x = 0;
int y = 0;
scanf("%d",&x);
if (0

If the sequence an is an equal ratio sequence, and A1 = 2, q = 3, BN = a3n-1, (n ∈ n *) find BN

If the sequence an is an equal ratio sequence, and A1 = 2, q = 3, BN = a3n-1, (n ∈ n *) find BN
=2,q=3
an=a1*q^(n-1)=2*3^(n-1)
bn=a(3n-1)=2*3^(3n-1-1)=2*3^(3n-2)
The yellow warbler sings, the green willow, the purple swallow cuts, the spring breeze, the warbler sings and the swallow dances

Can 32 times 0.9 simplify the calculation? If so, write down the formula

32×0.9
=32×（1-0.1）
=32-3.2
=28.8

The problem is 2,2,4,2,8,14,26,48,88, find the next number

2,2,4,8,14,26,48,88 ,162
There is one more 2 in the original sequence

A four digit number is the smallest prime number, a number on the one digit is the largest one digit, and a number on the hundred digit is the smallest natural number
The number on ten is more than the smallest sum. What's the number?

2059

Given the function f (x) = 4 ^ X / (4 ^ x + 2) (1), try to find f (a) + F (1)_ a) (2) find f (1 / 100) + F (2 / 100) +The value of F (99 / 100)

(1) F (a) + F (1-A) = 4 ^ A / (4 ^ A + 2) + 4 ^ (1-A) / [4 ^ (1-A) + 2] = 4 ^ A / (4 ^ A + 2) + 4 / [4 + 2 * 4 ^ A] = 4 ^ a / (4 ^ A + 2) + 2 / [2 + 4 ^ A] = (4 ^ A + 2) / [2 + 4 ^ A] = 1 (2) from (1), we can know that: F (1 / 100) + F (99 / 100) = 1F (2 / 100) + F (98 / 100) = 1... F (49 / 100) + F (51 / 100) = 1F 50 / 100 +

Please fill in the 10 numbers 1-10 in each circle of the cup below, so that the sum of the three numbers at the cup mouth, the sum of the four numbers in the middle of the cup, the sum of the four numbers on the vertical line of the center and the sum of the five numbers on the U-shape of the cup are equal to 25
0—0—0
0 0
0
0 0
0
0
As shown in the figure, there is a wired connection between 0 and 0, which can't be drawn here

It's impossible to fill in according to the given conditions
If the sum of the three numbers at the mouth of the cup and the four numbers at the diamond in the middle of the cup are all equal to 25, then the sum of the seven numbers is 50
And the sum of all ten numbers is 1 + 2 + +10=55
So the sum of the remaining three numbers is 55-50 = 5
But the minimum sum of three numbers is 1 + 2 + 3 = 6 > 5
Therefore, it is impossible to find the filling method that meets the conditions

1 is the factor of all nonzero natural numbers______ (judge right or wrong)

It is correct that 1 is the factor of all non-zero natural numbers

Which volume of mathematics book are integers and natural numbers in

Hebei Education Press grade 5 Volume 1 Chapter 1