The solution equation: x + y = 6 ①, 3x-3y = 6 ②

The solution equation: x + y = 6 ①, 3x-3y = 6 ②


x+y=6 ①,
3x-3y=6 ②
① X 3 + 2: x 3 + 2
6x=24
x=4
Substituting x = 4 into (1) yields:
4+y=6
y=2
So the solution of the equations is as follows:
x=4 y=2



X + Y-Z = 6 x-3y + Z = 1 3x + 2Y to solve the equation


If we add two forms to each other, we can get 2x-2y = 7, X-Y = 3.5 (four forms)
Formula 2 plus formula 3 gives 4x-y = 5 (formula 5)
5, x = 0. 5
Then y = - 3, z = - 8.5



Z = u ^ 2 ㏑ V, where u = Y / x, v = e (x ^ 3Y), then DZ =? (x ^ 3Y is the power of E)


z=(y/x)²lne^(x³y)=(y/x)²(x³y)=xy³
dz=y³dx+xdy³=y³dx+3xy²dy



When a batch of cement is transported to a construction site, one fourth of it is used on the first day, which is exactly one tenth of a ton. How many tons of this batch of cement in total


1 out of 10 (1 out of 4) = 1 out of 10 × 4 = 2 out of 5
So we can know: this batch of cement is 2 / 5 tons



As shown in the figure, the three sides of the right triangle are 3, 4, 5, EF, eg, ED, which are perpendicular to AB, BC, CA, and EF = eg = ed, then EF is calculated


The length of bfeg is x, then s △ ABC = s △ Abe + s △ BCE + s △ CAE, 12 × 3 × 4 = 12 × 3 × 4, 12 × 3 × 4 = 12 × AB, 12 × 3 × 4, 12 × 3 × 4 = 12 × AB, 12 × AB, 12 × AB, 12 × AB, 12 × AB, 12 × AB, 12 × ab × EF + 12 × BC, 12 × BC × eg + 12 × Ca, 12 × Ca, we will be the case of X, such as 12 × 3, such as s, 12 × 3, such as s △ ABC, s, 12 △ 3 △ Abe + AB, 12 × AB, 12 × AB, 12 × AB, 12 × ab × EF + 12 × AB, 12 × AB, 12 × AB, 12 × AB, 12 × AB, 12 × AB, 12 × AB, 12 × AB, 12 × AB, 12 × AB, 12 × 10, 12 × 10, 12 × 6, 12 × 8 + 12 × 12 × 6, 12 × 12 × B, 12 × & nbsp; & nbsp; X = 1. A: the bfeg side length of a square is 1



There is a pile of yellow sand on the construction site. One fourth of the total amount is used in the first day, and one third more is used in the second day than in the first day. There are still 15 tons left


15/[1-(1/4)-(1/4)*(4/3)]
=15/(5/12)
=36 tons
Square method: suppose there are x tons of yellow sand in total
(1/4)x+(1/4)x*[1+(1/3)]+15=x
(1/4)x+(1/3)x+15=x
(7/12)x+15=x
(5/12)x=15
x=15*12/5
=36
A: there are 36 tons of Huangsha



The formula of the symmetry of two straight lines about X and Y axes?


In terms of x-axis symmetry, y is replaced by - Y
For Y-axis symmetry, we change x to - X
On the origin symmetry, we change y to - y and X to - x at the same time



Three fifths of female workers are equal to male workers, and male workers account for ()% of the total number of employees


Three fifths of female workers are equal to male workers, and male workers account for (37.5%) of the total number of employees



If the quadratic trinomial 2x ^ 2-3x + m + 1 can decompose the factor in the range of real number, the value range of M can be obtained


It can be decomposed, that is, 2x & # 178; - 3x + m + 1 = 0 has real roots, and the discriminant is ≥ 0
9-8(m+1)≥0
8m≤1
m≤1/8



There are 20 boys and 30 girls in the school chorus. Boys account for (), while girls account for (). Boys are girls
The number of girls is () percent more than that of boys?


Boys are 40%, girls are 60%, boys are 66.6% of girls, girls are 50% more than boys