If f (x) is a linear function and 2F (1) + 3f (2) = 3, 2f (- 1) - f (0) = - 1, then f (x) is equal to () A. 4x9+y9B. 36x-9C. 4x9−19D. 9-36x

If f (x) is a linear function and 2F (1) + 3f (2) = 3, 2f (- 1) - f (0) = - 1, then f (x) is equal to () A. 4x9+y9B. 36x-9C. 4x9−19D. 9-36x

Let f (x) = ax + B, then 2 (a + b) + 3 (2a + b) = 32 (− a + b) − B = − 1, then 8A + 5B = 3 − 2A + B = − 1, a = 49b = − 19, so f (x) = 49x − 19, so choose C

Let f (x) be a linear function of X, and 2F (1) + 3f (2) = 3,2f (- 1) - f (0) = - 1, then f (x) is equal to?

Let f (x) = KX + B
f(1)=k+b f(2)=2k+b f(-)=-k+b f(0)=b
So, 2 (K + b) + 3 (2k + b) = 3 (1)
2(-k+b)-b=-1 (2)
The solution is: k = 4 / 9, B = - (1 / 9)
So, f (x) = 4 / 9x-1 / 9

If we know that f (x) is a linear function, 2f (2) - 3f (1) = 5, 2f (0) - f (- 1) = 1, then f (x) = ()
A. 3x+2B. 3x-2C. 2x+3D. 2x-3

∵ f (x) is a function of degree, Let f (x) = KX + B (K ≠ 0), and ∵ 2F (2) - 3f (1) = 5, 2f (0) - f (- 1) = 1, then there are: 2 (2k + b) − 3 (K + b) = 52 (0 + b) − (− K + b) = 1, the solution is: k = 3B = − 2, ∵ f (x) = 3x-2

Given 3f (x-1) + 2F (1-x) = 2x, find the analytic expression of the function

Let X-1 = y
Then 3f (y) + 2F (- y) = 2Y + 2 (1)
Let 1-x = y
Then 3f (- y) + 2F (y) = 2-2y (2)
3*(1)-2*(2)
5f(y)=6y+6-4+4y=10y+2
Then f (y) = 2Y + 2 / 5

X-5 / X-1 + 10x-10 / X-5 = 7

(x^-5)/(x-1)+(10x-10)/(x^-5)=7
Let k = (x ^ - 5) / (x - 1), then the original formula is transformed into
k+10/k=7
k^+10=7k
k^-7k+10=0
K = 2 or 5
From k = (x ^ - 5) / (x-1) = 2, we can get x = - 1 or 3
From k = (x ^ - 5) / (x-1) = 5, we can get x = 0 or 5
All of them meet the requirements, so x = - 1 or 3 or 0 or 5

Sin70 degrees sin60 degrees - sin20 degrees sin25 degrees
Break it down

I can't answer it right now. It's not easy to do at 25 degrees

Five times a number plus five is exactly 100, and this number is? (equation solution)

Let this number be X,
Then 5 * x + 5 = 100
5*X=95
X=19

If we know that Tan 2 / a = 2, Tan 2 / b = 1 / 3, then Tan (a + b)=

The solution Tana = (2tana / 2) / (1-tan & # 178; a / 2) = 4 / (1-4) = - 4 / 3tanb = (2tanb / 2) / (1-tan & # 178; B / 2) = 2 / 3 × (9 / 8) = 3 / 4 〈 Tan (a + b) = (Tana + tanb) / (1-tanatanb) = (- 4 / 3 + 3 / 4) / (1 + 1) = (- 16 / 12 + 9 / 12) × (1 / 2) = - 7 / 12 × 1 / 2 = - 7 / 24

If P (- 2,3), PQ = 4 and PQ is parallel to the Y axis, then the coordinates of point Q
A（-2,-1） B（2,3)
C(-2,1) D(-2,2）

If the point P (- 2,3), PQ = 4, PQ parallel to the Y axis, XQ = - 2; so | yq-3 | = 4; yq-3 = ± 4; yaq = 7 or YQ = - 1; then the coordinate of point q is aa (- 2, - 1) B (2,3) C (- 2,1) d (- 2,2) Hello, I'm glad to answer your questions, skyhunter 002 will answer your questions if

How much is 4 / 9 times 3 / 4

4 / 9 * 3 / 4 = 1 / 3