Is y = xcosx bounded in (- ∞, + ∞) and infinite when x →∞ Let x (k) = 2K π, (k = 1,2,3,...) why can we do this... Is the definition field of X not a real number

Is y = xcosx bounded in (- ∞, + ∞) and infinite when x →∞ Let x (k) = 2K π, (k = 1,2,3,...) why can we do this... Is the definition field of X not a real number

Y = xcosx is unbounded in (- ∞, + ∞). If x (k) = 2K π, (k = 1,2,3,...), then y (k) = 2K π, then the function is unbounded
Let x (k) = 2K π + π / 2, (k = 1,2,3,...), then y (k) = 0, then the function is not infinite
Let's use this example to illustrate that an unbounded quantity is not necessarily infinite

Let xcosx be the function and y be the function

y'=(x)'cosx+x(cosx)'
=cosx-xsinx

(x-3) of X + (2-3x of x) of (x + 6) = of (x-3)

x/(x-3)+(x+6)/(x²-3x)=(x-3)/xx²/x(x-3)+(x+6)/(x²-3x)=(x-3)/xx²/x(x-3)+(x+6)/x(x-3)=(x-3)/x(x²+x+6)/x(x-3)=(x-3)/xx(x²+x+6)=x(x-3)(x-3)x²+x+6=(x-3)²x²+x+6=x...

If the parabola y = 3x squared image moves 3 units to the right and 4 units to the down, then its fixed-point coordinates are______ The axis of symmetry is______
The analytic expression is________

The image of parabola y = 3x squared moves 3 units to the right, and then moves 4 units down to get y = 3 (x-3) ^ 2-4
Then its vertex coordinates are_ (3,-4)_____ The axis of symmetry is____ x=3__
Analytic formula y = 3 (x-3) ^ 2-4

How to calculate the density multiplied by the volume, for example: 0.9 × 10 & # 179; kg / M & # 179; × 3 × 10 negative cubic M & # 179; = 2.7kg?
Don't talk about formulas. I know,

Density times volume equals mass
0.9*10^3*3*10^(-3)＝0.9*3*10^3*10^(-3)＝0.9*3*1＝2.7

Clever calculation 1: (10.1-1.009-2) × 0.49 + 0.51 × (10.1-1.009 + 1)
Let 10.1-1.009 = a
.

Let 10.1-1.009 = a, then (10.1-1.009-2) × 0.49 + 0.51 × (10.1-1.009 + 1) = (A-2) × 0.49 + 0.51 × (a + 1) = (A-2) × 0.49 + 0.51 × (A-2 + 3) = (A-2) × 0.49 + 0.51 × (A-2) + 0.51x3 = (A-2) × (0.49 + 0.51) + 1.53 = A-2 + 1.53 = 10.1-1.009-2 + 1.53 = 10

If the focus f passing through the parabola y2 = - 6x makes a straight line with an inclination angle of 60 degrees and intersects with the parabola at two points a and B respectively, then the chord length AB is calculated

2p=6
p/2=3/2
So the guide line x = 3 / 2
Slope k = tan60 = √ 3
F(-3/2,0)
Then y = √ 3 (x + 3 / 2)
Substituting
3x²+9x+27/4=-6x
3x²+15x+27/4=0
Then X1 + x2 = - 5
For parabola, AF = the distance from a to the collimator
So AB = AF + BF
=Distance from a to guide line + distance from B to guide line
=|x1-3/2|+|x2-3/2|
=3/2-x1+3/2-x2
=3-(x1+x2)
=8

Hollow cylinder diameter 10 meters, height 17.6 meters, thickness 3.5 mm, density 7.85 * 1000 kg / m3, cylinder weight?

Outer diameter = 10m
Inner diameter = 10-0.0035 * 2 = 9.993m
H = 17.6m
Volume v = 3.14 × (square of outer diameter - square of inner diameter) × 4 × height = 3.14 × (square of 10 - square of 9.994) × 4 × 17.6 ≈ 1.934 M3
Weight = density × volume = 7.85 * 1000 * 1.934 ≈ 15178.5kg

Give me 60 more ways of factoring, 60 more ways of multiplication, 60 more ways of division

Here is the off form question
1）25%*132+1/4*8 2)32*0.125*25
=1/4*132+1/4*8 =(4+8)*0.125*25
=1/4*(132+8) =(4*25)*(8*0.125)
=1/4*140 =100*1
=35 =1000
3)75%*76+25*4+0.75*12
=3/4*76+3/4*12+25*4
=3/4*88+100
=166
4)3200*1/8÷2/5+1270 5)(2/3+4/5)*7/6
=400*5/2+1270 =22/15*7/6
=1000+1270 =77/45
=2270
5)6*(1/2+2/3) 6)132*(44÷176)
=6*1/2+6*2/3 =132*1/4 =33
=3+4
=7
7)72.25%*99+75.25%
=75.25%*99+75.25%*1
=75.25%*(99+1)
=75.25%*100
=75.25
1.3/7 × 49/9 - 4/3
2.8/9 × 15/36 + 1/27
3.12× 5/6 – 2/9 ×3
4.8× 5/4 + 1/4
5.6÷ 3/8 – 3/8 ÷6
6.4/7 × 5/9 + 3/7 × 5/9
7.5/2 -（ 3/2 + 4/5 ）
8.7/8 + （ 1/8 + 1/9 ）
9.9 × 5/6 + 5/6
10.3/4 × 8/9 - 1/3
11.7 × 5/49 + 3/14
12.6 ×（ 1/2 + 2/3 ）
13.8 × 4/5 + 8 × 11/5
14.31 × 5/6 – 5/6
15.9/7 - （ 2/7 – 10/21 ）
16.5/9 × 18 – 14 × 2/7
17.4/5 × 25/16 + 2/3 × 3/4
18.14 × 8/7 – 5/6 × 12/15
19.17/32 – 3/4 × 9/24
20.3 × 2/9 + 1/3
21.5/7 × 3/25 + 3/7
22.3/14 ×× 2/3 + 1/6
23.1/5 × 2/3 + 5/6
24.9/22 + 1/11 ÷ 1/2
25.5/3 × 11/5 + 4/3
26.45 × 2/3 + 1/3 × 15
27.7/19 + 12/19 × 5/6
28.1/4 + 3/4 ÷ 2/3
29.8/7 × 21/16 + 1/2
30.101 × 1/5 – 1/5 × 21
31.50＋160÷40 （58+370）÷（64-45）
32.120-144÷18+35
33.347+45×2-4160÷52
34（58+37）÷（64-9×5）
35.95÷（64-45）
36.178-145÷5×6+42 420+580-64×21÷28
37.812-700÷（9+31×11） （136+64）×（65-345÷23）
38.85+14×（14+208÷26）
39.（284+16）×（512-8208÷18）
40.120-36×4÷18+35
41.（58+37）÷（64-9×5）
42.(6.8-6.8×0.55)÷8.5
43.0.12× 4.8÷0.12×4.8
44.（3.2×1.5+2.5）÷1.6 （2）3.2×（1.5+2.5）÷1.6
45.6-1.6÷4= 5.38+7.85-5.37=
46.7.2÷0.8-1.2×5= 6-1.19×3-0.43=
47.6.5×（4.8-1.2×4）= 0.68×1.9+0.32×1.9
48.10.15-10.75×0.4-5.7
49.5.8×（3.87-0.13）+4.2×3.74
50.32.52-（6+9.728÷3.2）×2.5
36＋59＋41＋54
23×7＋23×3
1462－369－631
60506－19460÷35
23072÷412×65
184×38＋116×38－11300
(79691－46354)÷629
325÷13×(266－250)
74＋100÷5×3
(440－280)×(300－260)
100+25×3-90
12）90÷2＋136
70×74＋100÷5
38＋116×7＋23
369－（631 ÷5）×3
3/7 × 49/9 - 4/3
8/9 × 15/36 + 1/27
12× 5/6 – 2/9 ×3
8× 5/4 + 1/4
.6÷ 3/8 – 3/8 ÷6
4/7 × 5/9 + 3/7 × 5/9
5/2 -（ 3/2 + 4/5 ）
7/8 + （ 1/8 + 1/9 ）
9 × 5/6 + 5/6
3/4 × 8/9 - 1/3
7 × 5/49 + 3/14
6 ×（ 1/2 + 2/3 ）
8 × 4/5 + 8 × 11/5
31 × 5/6 – 5/6
9/7 - （ 2/7 – 10/21 ）
5/9 × 18 – 14 × 2/7
4/5 × 25/16 + 2/3 × 3/4
14 × 8/7 – 5/6 × 12/15
17/32 – 3/4 × 9/24
3 × 2/9 + 1/3
5/7 × 3/25 + 3/7
6.78*5.67
3.2*0.64=
4.8*1.25=
0.396÷1.2= 0.756÷0.36=
15.6×13=
0.18×15=
0.025×1.4 3.06×36=
5.76×3＝
0.04×0.12＝ 3.84×2.6≈
(keep one decimal place)
7.15×22=
90.75÷3.3 3.68×0.25
16.9÷0.13=130
1.55÷3.9 3.7×0.16
5.2× 1.6 8.4×1.3
13.76× 1.8= 6.4×0.5
4.48×0.4 5.25×5
35.4×4.2 0.76×0.32
0.25×0.046 2.52×3.4
1.08×25
425/25
75/3
768/12
342/23
567/3
674/56
92/2
121/11
132/11
133/2
145/15
56×67
78×9
82×4
For reference
3/14 ×× 2/3 + 1/6
1/5 × 2/3 + 5/6
9/22 + 1/11 ÷ 1/2
5/3 × 11/5 + 4/3
45 × 2/3 + 1/3 × 15
7/19 + 12/19 × 5/6
1/4 + 3/4 ÷ 2/3
8/7 × 21/16 + 1/2

The primitive function of LNX ^ 2 / x ^ 2

Original = ∫ LNX & # 178; / X & # 178; DX
=-∫2lnx d(1/x)
=-2∫lnx d(1/x)
=-2lnx ·1/x+2∫1/x dlnx
=-2lnx ·1/x +2∫1/x²dx
=-2/x ·lnx -2/x+c