What is the remainder of dividing 777 by 41

What is the remainder of dividing 777 by 41

Divide a set of seven (say 77777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777
The remainder are 7 (7 / 41), 36 (77 / 41), 39 (777 / 41), 28 (7777 / 41), 0 (77777 / 41), 7 (777777 / 41) respectively
It is concluded that the law of remainder is that every 5 numbers composed of 7 can be divided by 41
1996 divided by 5 to 1, then a 7 divided by 41 to 7
So the result is 7

3, - 5,7, - 13 is 24
Come on, it's due tomorrow. Use + - * / and () instead of power

1:(5 × 13 + 7) ÷ 32:((5 × 13) + 7) ÷ 33:(7 + 5 × 13) ÷ 34:(7 + (5 × 13)) ÷ 35:(7 + 13 × 5) ÷ 36:(7 + (13 × 5)) ÷ 37:(13 × 5 + 7) ÷ 38:((13 × 5) + 7) ÷ 3

How to judge the order of differential equation XYY '' + X (y ') ^ 3-y ^ 4Y' = 0

The order of the differential equation is only related to the order of the highest derivative, so the equation is of order 2

How many cubic meters of water is a liter of water?
I want the correct answer. 1 cubic meter of water doesn't seem to be equal to 1 liter of water. I want experts to give me an answer

One liter of water is equal to 0.001 cubic meter of water, 1 cubic meter = 1000 liters

Fifth grade vertical calculation 20

1.(0.24+0.06)×12+0.4 2.1.8×1.6+1.5×（1.6+1.4） 3.350×1.8 4.2.07×53 5.1.92×14 6.7.06×2.7-5.7 7.102×0.45 8.3.14×3.9 9.9.8×25 10.1.5×102 11.0.038×5×2.1 12.2.02×8.5 13.1.25+4.6+0.75 14.48×0.25 15.12.5×9.6 16.0.75×102 17.948÷（38+41） 18.675÷（12.6+14.4） 19.19÷[（0.75+0.2）×2] 20.（2480-100×20）÷120 If LZ doesn't think it's enough, ask me again

Determinant X - 10.000 X - 1.00.000. X - 1 a0a1 A2.. an-1 an
[x - 10..... 0 0] [0 X - 1..... 0 0]...... [0 0..... X - 1] [A0 A1 A2.. an-1 an] this is a determinant of order n + 1

The determinant C1 + XC2 + x ^ 2c3 +... + x ^ NCN + 1 is equal to 0 - 1 0... 0 0 0 X - 1... 0... 0 0 0... X - 1a0 + a1x + a2x ^ 2 +... + anx ^ n A1 A2.. an-1 an is expanded according to the first column, and the determinant = (A0 + a1x + a2x ^ 2 +... + anx ^ n) * (- 1) ^ (n + 1 + 1) * - 1 0... 0 X - 1... 0

7x-13.21=5x+16.

7x-13.21=5x+16.39
7x-5x = 16.39 + 13.21
2x=29.6
x=29.6∕2=14.8

A barrel of oil with a barrel weighs 95 kg. After 1 / 2 of the oil is poured out, the oil and barrel still weigh 50 kg. How many kg does the original oil and barrel weigh?
There should be a formula

95-50 = 45 kg
45 * 2 = 90kg
95-90 = 5kg
Oil 90kg
5 kg per barrel

Judge the continuity and differentiability of function at x = 0!
=0: y = x ^ 2Sin (1 / x);
When x = 0, y = 0;
Judge the continuity and differentiability of the piecewise function at x = 0

It's too "essence" upstairs. It can't be used by definition
X tends to 0 and y to zero (bounded quantity multiplied by infinitesimal quantity)
So continuous
Solving Lim {x → 0} (Y (x) - Y (0)) / (x-0) directly without dividing left and right derivatives
So it can be derived

Let abcdmn be int type variables, and a = 5, B = 6, C = 7, d = 8, M = 2, n = 2, then after the operation of logical expression (M = a > b) & & (n = C > d), the value of n is

Still 2