Given f (x) + 2F '(1) - ln (x + 1) = 1. (1) find the expression of function y = f (x)

Given f (x) + 2F '(1) - ln (x + 1) = 1. (1) find the expression of function y = f (x)

From F (x) + 2F '(1) - ln (x + 1) = 1, we can get f (x) = - 2F' (1) + ln (x + 1) + 1. The derivation shows that f '(x) = 1 / (x + 1), so f' (1) = 1 / 2
So f (x) = ln (x + 1)

Is the function ln (LNX) equal to x

Not equal to
Ln (LNX) is the simplest form, there is no specific steps
It's two logarithms of X
I'm very happy to answer for you, and the learning dictionary team will answer for you
Please click the [select as satisfactory answer] button below,

What is ln (LNX) equal to?

Y = ln (LNX) is a function whose domain of definition is (1, + infinity) (- infinity, + infinity)

It is known that when a takes a real number in a certain range, the value of the algebraic formula (2 − a) 2 + (a − 3) 2 is a constant, then the constant is ()
A. -1B. 0C. 1D. 5

The original formula = | A-2 | + | A-3 |, when a ≤ 2, the original formula = - A + 2-A + 3 = - 2A + 5; when 2 < a ≤ 3, the original formula = a-2-a + 3 = 1; when a > 3, the original formula = A-2 + A-3 = 2a-5, so when a takes a real number in a certain range, the value of the algebraic formula (2 − a) 2 + (a − 3) 2 is a constant, then the constant is 1. So choose C

The length of the express train is 70m and the length of the local train is 80m. If the express train runs in the same direction, the time from catching up with the local train to leaving the local train is 20s. If the express train runs in the opposite direction, the time between two trains is 20s
The express train is 70m long and the local train is 70m long
80 M. if the two trains run in the same direction, the time from catching up with the local train to leaving the local train is 20 s. if the two trains run in opposite directions, the time from meeting to leaving is 4 s. how many kilometers do the two trains travel per hour?

Let the slow speed be x and the fast speed be y
(y-x)*20=70+80
(y+x)*4=70+80
There is Y-X = 7.5
y+x=37.5
The speed of express train is y = 22.5m/s = 81 km / h
Slow speed x = 15m / S = 54km / h

It is known that the focus of the hyperbola is on the y-axis, and the coordinates of two points P1 and P2 on the hyperbola are (3,4, root sign 2). (9 / 4,) respectively

The obtained standard equation and the original quasi equation are symmetric with respect to y = x, and the given two pairs of values x, y exchange positions are substituted into the original standard equation, and then the equations are solved to find a, B

There are 276 tons of cement in the construction site. 36 tons are used in the first day, and the remaining 3 / 8 are used in the second day?

276-36=240
240*3/8=90
36+90=126
Two days share to cement 126 tons

In sector AOB, ∠ AOB = 120 ° OA = 1, point C is on arc AB, if the vector OC = xoa + yob x y ∈ R is used to find the maximum value of X + y, the following description is wrong

We can get the constraint conditions according to the topic, x ^ 2 + y ^ 2 - xy = 1, x > = 0, Y > = 0. Finding the maximum value of X + y can be converted to finding the minimum value of - X-Y. then I calculate it with MATLAB.% CF.mfunction [c,ceq] = CF(x)ceq = x(1)^2 - x(1)*x(2) + x(2)^2 - 1;c = [];% main.mf ...

A pair of yellow sand transported six cars to transport three seventh of them, and how many cars will the rest be transported

We need more vehicles
=6 △ 3 / 7-6
=6 × 7 / 3-6
=14-6
=8 cars
Your adoption is the driving force of my answer!

On the axisymmetric linear equation of the line y = - 1 with the line 3x-y + 5 = 0

3x + y + 7 = 0 hope useful