English experts come in and have a look Wenbo. What are the words with similar pronunciation in English? That is to say, the English pronunciation is the English word of "Wenbo". Please recommend a few more. If not, the pronunciation is similar If you are satisfied, you will get extra points It's better to add the meaning of English words It's for a girl. Similar sounds are OK. There's no need to sound too similar. Just use it well. Add another 30

English experts come in and have a look Wenbo. What are the words with similar pronunciation in English? That is to say, the English pronunciation is the English word of "Wenbo". Please recommend a few more. If not, the pronunciation is similar If you are satisfied, you will get extra points It's better to add the meaning of English words It's for a girl. Similar sounds are OK. There's no need to sound too similar. Just use it well. Add another 30


Weber / Weber / Webb ['Web & # 601;] Chinese spelling: Weber's name meaning: Weaver's name source: German 2. Wilbert ['wilb & # 601; t] Chinese spelling: Wilbert's name meaning: willing, brilliant name source: ancient German 3. Vann



What words do you pronounce in English?


Colour or color
It means: color



The circumference of a square is equal to the circumference of a circle. If the radius of the circle is 15 cm, what is the side length of the square and what is the area of the circle


The area of the circle is 3.14 × 15 × 15 = 706.5 square centimeter;
Square side length = 3.14 × 2 × 15 △ 4 = 23.55 cm;
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As shown in the figure, it is known that s is a point out of the plane of the parallelogram ABCD, m and N are points on SA and BD respectively, and SMMA = bnnd. Then the line Mn______ Plane SBC


It is proved that bnnd = bgag can be obtained by making ng ‖ ad through N, intersecting AB with G and connecting mg. According to the known condition bnnd = SMMA, SMMA = bgag, ⊄ mg ‖ sb. ⊄ mg ⊄ plane SBC, sb ⊂ plane SBC, ⊂ mg ‖ plane SBC. Ad ‖ BC, ⊄ ng ‖ BC, ng ⊄ plane SBC, BC ⊂ plane SBC ⊂ ng ‖ plane SBC



It is known that the circumference of a sector is 40. When its radius and central angle are taken, what is the maximum area of the sector? What is the maximum area?


Let R be the radius
Arc length = 40-2r
Area s = R (40-2r) / 2 = - R ^ 2 + 20R = 100 - (r-10) ^ 2
When r = 10, the maximum area s is 100
At this point, the center angle = (40-2r) / r = 2 (radian) = 360 / π (angle)



Let Sn be the sum of the first n terms of the arithmetic sequence {an}, if A1 = 1, A3 = 5, SK + 2-sk = 36, then the value of K is


Because an is an arithmetic sequence, the general formula of an is an = a * n + B
From A1 = 1, A3 = 5
a+b=1
3a+b=5
The solution is a = 2, B = - 1
So the general formula is an = 2 * n-1
Sn=2*n-1+2*(n-1)-1+..+1
Sn+Sn=(a1+a2+...+an-1+an)+(an+an-1+...+a2+a1)=(a1+an)+(a2+an-1)+...+(an-1+a2)+(an+a1)=(2n-1+1)+(2n-3+3)+...+(3+2n-3)+(1+2n-1)=2n*n=2n^2
So Sn = n ^ 2
Sk+2-Sk=(k+2)^2-k^2=k^2+4k+4-k^2=4k+4=36
4k=32
k=8
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"Add waist to poetry" explains that words should be used in order to make the article more expressive?


Learning "to add waist to poetry" shows that words should be used (accurately and vividly) to make the article more vivid and vivid!



If the distance between the vertex and the origin of the image of quadratic function y = x2-6x + C is 5, then C=______ .


∵ the vertex coordinates of the image of quadratic function y = x2-6x + C are (3, C-9), ∵ 32 + (C-9) 2 = 52, and the solution is C = 13 or C = 5



A cuboid is 8 cm in length, 8 / 5 in width and 2 cm in height. The surface area of the cuboid is () square centimeter, and its volume is () cubic centimeter?


The width of the cuboid is 8 × 8 / 5 = 5cm
The surface area is equal to 2 × (8 × 5 + 8 × 2 + 5 × 2) = 132 square centimeters
The volume is 8 × 5 × 2 = 80 cubic centimeters
A: the surface area of this cuboid is (132) square centimeters, and the volume is (80) cubic centimeters



Given Sina = 2 / 3, a ∈ (π / 2, x), CoSb = - 3 / 4, B ∈ (π, 3 / 2 π), find cos (a-b), cos (a)
The last cos (a) is cos (a + b)


Sina = 2 / 3, sin ^ 2A = (2 / 3) ^ 2, 1-cos ^ 2A = 4 / 9 ∵ a ∈ (Π / 2, Π), cosa = - √ 5 / 3 by the same principle: SINB = - √ 7 / 4cos (a-b) = cosacosb + sinasin B = (- √ 5 / 3) (- 3 / 4) + 2 / 3 (- √ 7 / 4) = (3 √ 5-2 √ 7) / 12cosa + b) = cosacosb sinasin B = (- √ 5 / 3) (-...)