If the height of a cylinder is shortened by 6cm, its surface area will be reduced by 75.36cm2 and its volume will be reduced______ Cubic centimeter

If the height of a cylinder is shortened by 6cm, its surface area will be reduced by 75.36cm2 and its volume will be reduced______ Cubic centimeter

The radius of the bottom surface is: 75.36 △ 6 △ 3.14 △ 2 = 2 (CM), so the reduced volume is: 3.14 × 22 × 6 = 75.36 (cm3). A: the volume is reduced by 75.36 cm3. So the answer is: 75.36

This willow tree is about two fold thick. Its thick leaves cover more than 100 square meters of shade. Its trunk and branches are thick
Now the color of iron ingot is thick and hard
This is a peach tree——————————————————————————————————————————————————————————————————————————————————

Leaves ovate lanceolate, margin densely serrate, glabrous on both sides or sideburns between axils of lower veins; flowers solitary, first leaves open, subsessile; calyx tube bell, short villi, lobes ovate; petals pink,

When the fulcrum is 30cm away from the thick end, the stick can maintain horizontal balance. If the fulcrum is 50cm away from the thick end, which end should be hung with multiple objects to restore horizontal balance?

When the fulcrum is 30cm away from the thick end, the stick can keep horizontal balance, which indicates that this point is the position of the center of gravity of the stick
When the fulcrum is moved to 50cm away from the thick end, a suitable weight must be hung at the thin end to restore the horizontal balance of the stick
Let G be the gravity of the weight
G*40cm=19.6N*(50cm-30cm)
G=9.8N

Use five small squares with side length of 2cm to form a large rectangle. What are the perimeter and area of the rectangle?
Urgent need!!!!!! thank you!!!!!!

Length 10
Width 2
Perimeter (10 + 2) * 2 = 24cm
Area 10 * 2 = 20cm ^ 2

Simple calculation 0.45 * [4.85 / (3.8 / 1.9) + 3.6-1.56 * 2.07] = 1.25811, please decompose the process
Please use the simple calculation method

0.45*[4.85/(3.8/1.9)+3.6-1.56*2.07]
=0.45[4.85/2+3.6-3.2292]
=0.45(2.425+3.6-3.2292)
=0.45*2.7958
=1.25811

The function f (x) = (AX + 1) / (x + 2) (a is a constant). When x ∈ (- 1,2), the range of F (x) is (- 3 / 4,3), and the value of a is obtained

f(x)=a+(1-2a)/(x+2)
Then f is monotone on (- 1,2)
When 1-2a1 / 2, f increases monotonically
Then f (- 1) = - 3 / 4, f (2) = 3
1-A = - 3 / 4, (2a + 1) / 4 = 3 has no solution
When 1-2a > 0, a

A cuboid is 2cm long and 1cm wide. If the circumference of the stacked figure is 26cm, how many layers should it be stacked

Circumference of a rectangle = (2 + 1) * 2 = 6cm
Therefore, it is necessary to stack (26-6) △ 2 = 10 layers
Oh, cuboid? High?

Use 1,2,9,11 to do four operations, so that the result is equal to 24
There are two more questions: (1) 3 7 10 13 (2) 2 6 7 10

(1+2)*11-9=33-9=24;

In the sequence {an}, A1, = 1, Sn is the sum of the first n terms. When t > 0, there is 3tsn - (2t + 3) sn-1 = 3T (n ∈ n *, n ≥ 2)
(1) Prove that the sequence {an} is an equal ratio sequence;
(2) Let the common ratio of the sequence {an} be f (T), make the sequence {BN} such that B1 = 1, BN = f () (n ∈ n *, n ≥ 2), and find the first n terms and BN of the sequence {BN}
In the sequence {an}, A1, = 1, Sn is the sum of the first n terms. When t > 0, there is 3tsn - (2t + 3) sn-1 = 3T (n ∈ n *, n ≥ 2)
(1) Prove that the sequence {an} is an equal ratio sequence;
(2) Let the common ratio of the sequence {an} be f (T), and make the sequence {BN} such that B1 = 1, BN = f (1 / 3bn-1) (n ∈ n *, n ≥ 2), then find the first n terms and BN of the sequence {BN}.

A n-1 equation is constructed, that is, 3tsn-1 - (2t + 3) sn-2 = 3T
3tSn-(2t+3) Sn-1 =3t
Subtraction of two formulas
3t(Sn-Sn-1)+(2t+3)(Sn-2-Sn-1)=0
3tan-(2t+3)an-1=0
3tan=(2t+3)an-1
an/an-1=(2t+3)/3t=2/3+t
(2) So the coefficient of F (T) = 2 / 3 + T B1 = 1 t is - 2 / 1
So BN = 2 / 3-2 / N, which is an arithmetic sequence, the rest will not be written

Decorate a sitting room to need 80 with the square brick of side length 5 decimeters, if change to the square brick of side length 4 decimeters to need how many meters
equation

5 × 5 × 80 (4 × 4) = 125 pieces