In the circle O, if the center angle AOB is 90 ° and the distance from the point O to the chord is 5, what is the diameter and length of the circle O? In the circle O, if the center angle AOB is 90 ° and the distance from the point O to the chord is 4, what is the diameter and length of the circle O? In the circle O, if the center angle AOB is 90 ° and the distance from the point O to the chord is 5, what is the diameter and length of the circle O? It's five, not four

In the circle O, if the center angle AOB is 90 ° and the distance from the point O to the chord is 5, what is the diameter and length of the circle O? In the circle O, if the center angle AOB is 90 ° and the distance from the point O to the chord is 4, what is the diameter and length of the circle O? In the circle O, if the center angle AOB is 90 ° and the distance from the point O to the chord is 5, what is the diameter and length of the circle O? It's five, not four

If the string is an ab string, the diameter is 8 * root 2

Solution ratio: 0.5:0.25 = 5x: 4

0.5∶0.25 = 5x∶4
0.5×4 = 0.25×5x
2 = 1.25x
x = 1.6

If the diagonal length of a parallelogram is x, y and one side is 12, then the value of X, y may be ()
A. 8 and 14b. 10 and 14C. 18 and 20d. 10 and 34

A. 82 + 142 = 4 + 7 = 11 < 12, so impossible; B, 102 + 142 = 5 + 7 = 12 = 12, so impossible; D, 34-10 = 24, so impossible; so choose C

Solving the equation: x-x / 12-x / 7-x / 8-x / 4-x / 20-x / 5 = 30 + 120 + 300 + 50

x-x/7-(x/12+x/8)-(x/4+x/20+x/5)=500
x-x/7-(5/24)x-x/2=500
(1/2-5/24)x-x/7=500
(7/24)x-x/7=500
49x-24x=500*24*7
25x=500*24*7
x=20*24*7
x=3360

Given that the tangent slope of the image with function f (x) = x / 2-sinx / 4 - √ 3cosx / 4 at point a (x0, f (x) is 1 / 2, then the value of tan2x0
I don't know about tan2xo = 2tanxo / 1-tan & # 178; XO in some parts of your previous answers. How did this come from? Tan & # 178; XO and how to ask for this

Function derivation, f '(x) = 1 / 2 - 1 / 4sin (x / 4) + √ 3 / 4cos (x / 4), because f' (x0) = 1 / 2, we can find x0. Tan2x0 = sin2x0 / cos2x0 = (2cosx0sinx0) / (COS & # 178; XO Sin & # 178; x0), the numerator and denominator are divided by cos & # 178; x0

Rational numbers are integers, fractions, positive rational numbers, negative rational numbers and zeros

No, I repeat
Rational number is the sum of integer and fraction
In other words, rational number is the general name of positive rational number, negative rational number and zero

The known function f (x) = ln (x + √ X & # 178; + 1)
(1) Find the domain of F (x);
(2) Judge the parity of F (x) and prove it

(1)∵x+√(x^2+1)>0∴x∈R
(2)f(-x)+f(x)=ln[√(x^2+1)+x][√(x^2+1)-x]=ln(x^2+1-x^2)=ln1=0
Ψ f (- x) = - f (x), which is an odd function

The product of 3 and 5 / 7 and "is 1", and the reciprocal of "is itself

The product of 3 and 5 / 7 and 7 / 26 is 1, and the reciprocal of 1 is itself

Using factorization method to solve the equation, 4 (Y-3) ^ 2-25 (y ^ 2-4y + 4) = 0
I wanted to use the difference of squares to calculate half of it

4(y-3)^2-25(y^2-4y+4)=0
4(y-3)^2-5(y-2)^2=0
(2y-6)^2-(5y-10)^2=0
(2y-6+5y-10)(2y-6-5y+10)=0
(7y-16)(4-3y)=0
y1=16/7 y2=4/3

The number of zeros of function f (x) = 2x & # 179; - 6x & # 178; + 7 in (0,2) is

Function f (x) = 2x & # 179; - 6x & # 178; + 7
F (x) derivation = 6x ^ 2-12x = 6x (X-2)
Let f (x) = 0, then X1 = 0, X2 = 2
X1 and X2 are two turning points of function f (x)
f(0)=7>0
f(2)=2x8-6x4+7=-1