If the solution of the equation ax-3x = 3 about X is a positive integer, then the value of a is?

If the solution of the equation ax-3x = 3 about X is a positive integer, then the value of a is?


ax-3x=3
(a-3)x=3
∵ the solution is a positive integer
The integer A-3 is a positive factor of 3
A-3 = 1 or 3
That is, a = 4 or a = 6



If the solutions of equation 13X = 1 and 2x + a = ax are the same, then the value of a is ()
A. 2B. -2C. 3D. -3


Solve the first equation: x = 3, solve the second equation: x = AA − 2  AA − 2 = 3, solve: a = 3, so choose C



For any real number x, there is a real number y such that x + Y > 0. Write the negation of this proposition and explain the reason


For any real number x, y, x + y ≤ 0



A and B trains leave from both sides at the same time. The speed of a train is 54 kilometers per hour, and that of B train is 53 kilometers per hour. After 4 hours, how many kilometers is the length of the railway between the two cities?


(54+53)*4=428



The average of the three numbers is 6, and the ratio of the three numbers is 12:23:56. The largest of the three numbers is 6______ .


3 × 6 = 18, 12:23:56 = 3:4:5, 18 × 53 + 4 + 5, = 18 × 512, = 7.5



The distance between a and B is equal to the distance between B and C. the speed of B is 80% of the speed of A. It is known that B starts 11 minutes earlier than a, but stops at B for 7 minutes, and a keeps on driving to C. finally, B arrives at C 4 minutes later than a. then, after B starts, B starts______ The first car will overtake the second car in 15 minutes





From 1 to 300, what is the sum of the remaining natural numbers after removing all the perfect squares?


1 -- 300, the minimum square is 1 & # 178; = 1, the maximum is 17 & # 178; = 289
1+2+3+...+300-(1²+2²+...+17²)
=(1+300)×300÷2-17×(17+1)×(2×17+1)÷6
=45150-1785
=43365



The distance between a and B measured on the map with scale of 1 / 6000000 is 10cm. A and B trains leave from a and B at the same time and meet at 6 o'clock
The speed ratio of the train is 11:9. When the two cars meet, how many kilometers does car a travel


10 △ 1 / 6000000 = 6000000cm = 600km
600 △ 6 = 100 km (speed and speed)
100 ÷ (11 + 9) × 11 = 55 km (speed of vehicle a)
When the two cars met, car a traveled 55 × 6 = 330 km
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Find the minimum value of a which makes x + y ≤ ax + y (x > 0, Y > 0) constant


Since the value of a is a positive number, the square of both sides of the known inequality is: x + y + 2XY ≤ A2 (x + y), that is, 2XY ≤ (A2-1) (x + y), ① ﹥ x, Y > 0, ﹥ x + y ≥ 2XY, ② if and only if x = y, there is an equal sign in ②. Comparing ① and ②, the minimum value of a satisfies A2-1 = 1, ﹥ A2 = 2, a = 2 (because a > 0), and the minimum value of a is 2



For a pile of coal, 600 tons are transported in the first day, which accounts for just one sixth of the pile of coal. The ratio of the coal transported in the second day to the pile of coal is 1:5?
For a pile of coal, 600 tons are transported in the first day, which accounts for just one sixth of the pile of coal. The ratio of the coal transported in the second day to the pile of coal is 1:5. How many tons are transported in the second day?


Total: 600 / (1 / 6) = 3600 the next day: 3600 * (1 / 5) = 720