Given that the solution of the equation 1 / 3x = 1 and 2x + a = ax about X are the same, what is the value of a?

Given that the solution of the equation 1 / 3x = 1 and 2x + a = ax about X are the same, what is the value of a?

1 / 3x = 1, the solution is x = 3
SO 2 × 3 + a = 3A
3a-a=6
2a=6
a=3

When the equation 3x + 4 = 2x and ax + 3x = 2 have the same solution, what is the value of a?

From the equation 3x + 4 = 2x, x = - 4
Substituting x = - 4 into ax + 3x = 2, - 4a-12 = 2
4a=-12-2=-14
a=-7/2

Solve the following equation (1) ax + B = C (a is not equal to 0) (2) mx-2 = 3x + n (M is not equal to 3)

（1）ax=c-b
x=(c-b)/a
(2)mx-3x=n+2
(m-3)x=n+2
x=(n+2)/(m-3)

Solve the equation of X: MX + M = x (M is not equal to 1:2), ax-b = 3x

mx+m=x
x-mx=m
(1-m)x=m
x=m/(1-m)
ax-b=3x
ax+3x=b
(a+3)x=b
A = - 3, B = 0, there are innumerable solutions
A = - 3, B ≠ 0, no solution
a≠-3,x=b/(a+3)

Given that ab > 0, try to compare the difference cube root of (a) - (b) and a-b

[(A-R) - (B-R)] ^ 3 - (a-b)
=[a-b-3 (AB) open cube root * (a-b-b open cube root)] - (a-b)
=-3 (AB) open cube root * (a open cube root - B open cube root)
Because AB > 0
Therefore, when a > b, a open cube root - B open cube root > 0
[(A-R) - (B-R)] ^ 3 - (a-b)

When they met at six hours, a traveled 48 kilometers more than B. It is known that the speed of car B is five sixth of that of car A. how many kilometers do the two stations meet

The speed of car a is x, and that of car B is 5 / 6x
6X-5/6X×6=48
1/6X=8
X=48
48×5/6=40
6×(48+40)=528

Solve the following inequality system: {3 (X-2) + 8 & gt; 2x, x + 1 / 3 ≥ x-x-1 / 2

3(x-2)+8>2x
3x-6+8>2x
3x-2x>-2
x>-2
x+1/3≥x-x-1/2
x+1/3 ≥x-1/2x+1/2
x+1/3≥1/2x+1/2
x-1/2x≥1/2-1/3
1/2x≥1/6
x≥1/3
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The distance between a and B is 720 km. The passenger cars and freight cars leave each other from the two places. After 3.6 hours of meeting, the speed ratio of the passenger cars and freight cars is 3:2, and the passenger car speed ratio is 3:2
How many kilometers does the car travel per hour? Use the equation to solve

The speed ratio of passenger cars to freight cars is 3:2
Suppose the speed of passenger car is 3x and that of freight car is 2x
3.6(3x+2x)=720
5x=200
x=40
3x=120
2x=80
The speed of passenger cars is 120 km / h; the speed of freight cars is 80 km / h

We know that vector a = (- 2,1) vector b = (x, 1) if the angle between vector a and vector B is obtuse
Given vector a = (- 2, - 1) vector b = (x, 1) if the angle between vector a and vector B is obtuse, then the value range of X? I calculate that, - 1 is less than the square of root sign 5 * the square of root sign X-1 is less than 0 - 2x-1x > - 1 / 2. What should I do next

The necessary and sufficient condition of X is: (- 2) x + (- 1) * 1-1 / 2 and X is not equal to 2
So the value range of X is x > - 1 / 2 and X is not equal to 2
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Hope to help you!

If one fifth of the number of people in the first team is transferred to the second team, the number of people in the two teams will be equal

The first team is unit 1
Transfer in 1 / 5, go to 2 teams, leave 4 / 5
At this time, team 2 is 4 / 5
The original team 2 4 / 5-1 / 5 = 3 / 5
The ratio of team 1 to team 2 = 1:3 / 5 = 5:3