Solution equation: 1.4 * (x + 24) = 3x-24

Solution equation: 1.4 * (x + 24) = 3x-24

1.4x+33.6=3x-24
1.6x=57.6
x=36

Solution equation: X (3x-4) = 3x (x-3) - 10

x(3x-4)=3x(x-3)-10
3x²-4x=3x²-9x-10
5x=-10
x=-2

It is proved that the limit does not exist: the limit of (x + y) / (X-Y) when (x, y) tends to (0,0)
Is it because the domain D = {(x, y) | x is not equal to y}? Where to start,

Along two straight lines, y = 2x
When y = - 2x tends to (0,0)
The limits are - 3 and - 1 / 3 respectively
The definition of the existence of limit requires that the limit is equal to any line passing (0,0)
So there is no limit

(a = 3, B = 5, B + = a, C = b * 5) the value of a comma expression
Please master the calculation, it's better to write the steps,

The first two expressions are just assignments, starting from the third,
b+=a,
That is, B = B + A,
That is, B = 5 + 3,
b=8,
Find the last expression,
c=b*5,
c=8*5,
c=40.
Because the value of the comma expression is the value of the last expression, the values of some expressions are 40, and the final values of other variables are a = 3, B = 8, C = 40

Ancient poems describing the Three Gorges of the Yangtze River

On the problem of finding limit with Taylor formula
Using Taylor formula to find the limit of LIM (e ^ x * SiNx - x (1 + x)) / (x ^ 3) when x tends to 0
Is that right
Molecule = (e ^ x * SiNx - x (1 + x)) = [1 + X + x ^ 2 / 2 + O (x ^ 2)] [x + O (x)] - x (1 + x) = x ^ 3 / 2 + O (x ^ 3)
Add the denominator to get 1 / 2, and the reference answer is
.(e^x * sinx - x(1+x))
=[1 + x + x^2/2 + o(x^2)][x - x^3/6 + o(x^3)] - x(1+x) = x^3/3 + o(x^3)
One third in the end
The SiNx of the answer is more than me. Why is it like this? Why is my SiNx wrong?

It is not appropriate for you to develop SiNx into x + O (x ^ 3), because the first term of e ^ x expansion multiplied by SiNx is a constant term, so the x ^ 3 term of SiNx is not infinitesimal of higher order for molecules, and is of the same valence, so the expansion of the reference answer is right

Boys account for 5 / 9 of the total number in class 52. After 4 girls are transferred, boys now account for 3 / 5 of the total number

The ratio of boys to girls: (1-5 / 9) / (5 / 9) = 4 / 5
Now the proportion of boys in girls is: (1-3 / 5) / (3 / 5) = 2 / 3
Now the same number of boys as before: 4 / (4 / 5-2 / 3) = 30
Now the number of students in the class is 30 / (3 / 5) = 50

In 15, 27, 19, 25, 30, 29, 31, x, the median is 24, then x is equal to ()~~
In an hour~

16

Write a general formula of the following sequence: 1, 0, - 13, 0, 15, 0, - 17, 0

When n is even, an = 0; when n is odd, if n = 4K + 1, then an = (- 1) n + 1 · 1n; if n = 4K + 3, then an = (- 1) n · 1n (K ∈ n)

There are 45 pieces of RMB 10 and RMB 5, totaling 325 yuan. How many pieces of RMB 5 and RMB 10?

It's like the problem of chicken and duck in the same cage, (45 * 10-325) / 5 = 25 is 5 yuan