Input x divided by 7 minus 3 times 3 and output 33 equations,

Input x divided by 7 minus 3 times 3 and output 33 equations,

3(x/7-3)=33 ,
x/7-3=11 ,
x/7=14 ,
x=98 .

(x+8-60%x)\60%x=75%
X is not a multiply sign, every step should be detailed, and it's better to have notes. (wealth is limited, I can't give too much, sorry)

(x+8-60%x)\60%x=75%
(x + 8-0.6x) / (0.6x) = 0.75 ← ← (change percentage to decimal)
0.4x + 8 = 0.45X ← ← (multiply both sides by the denominator and simplify the left side)
0.05x = 8 ← ← (shift)
X = 160 ← ← (coefficient reduced to 1)

How to solve the equation (2-75%) x = 36

According to the meaning of the title:
(2-0.75)x=36
1.25x=36
x=28.8

A simple algorithm of 66 times 99 plus 64

66 times 99 plus 64
=66*（100-1）+64
=66*100-66+64
=6600-2
=6598

A thin-walled glass tube with uniform inner diameter and mercury were used in the Torricelli experiment
The weight is g. the cross-sectional area of the tube is 5, and the glass tube is inserted vertically in the mercury tank as shown in the figure,
The length of the mercury column in the tube is ^, the atmospheric pressure is P0, the mercury density is p, and the operation is correct
If the glass tube is lifted up vertically by hand so that the nozzle does not leave the mercury surface in the tank, then
The size of human pull f is
A．G B．G-PoS C．G+Pos D．G-pghs

C
F=G+P0S
Because the mercury in the tube is held by atmospheric pressure, no one needs to lift it
Taking the glass tube as the analysis object, the vertical direction of the glass tube is only affected by the downward pressure of the atmosphere on the top of the tube, the gravity of the tube and the pulling force of people
Although mercury is in the tube, there is no force on the tube in the vertical direction, and the three forces are balanced, so f = G + P0S

The base and area of a triangle are equal to those of a parallelogram. The height of parallelogram is 10cm, and the height of triangle is ()
A. 10cmB. 20cmC. 5crn

Let the height of triangle be H1, the height of parallelogram be H2, because H1 = 2S △ a, h2 = s △ a, so h2 = 12h1, so the height of triangle is twice that of parallelogram, and the height of triangle is: 10 × 2 = 20 (CM)

Simple calculation 4.8-3.62-0.38 + 0.2

（4.8+0.2）-（3.62+0.38）

Mathematics off form calculation in the first semester of grade 6 (simple calculation of scores)
Please! It's urgent!
(help with the questions, it's better to bring the answers)

1 / 5 × 6 + 4 / 5 × 6 = (1 / 5 + 4 / 5) × 6 = 1 × 6 = 6

As shown in the figure, it is known that the quadrilateral ABCD is a parallelogram. On the extension line of AB, intercept be = AB, BF = BD, connect CE and DF, and intersect at point M. verification: CD = cm

It is proved that: ∵ quadrilateral ABCD is a parallelogram, ∵ AB is parallel and equal to DC. And ∵ be = AB, ∵ be is parallel and equal to DC. The ∵ quadrilateral bdce is a parallelogram. ∵ DC ∵ BF, ∵ CDF = ∵ F. similarly, ∵ BDM = ∵ DMC. ∵ BD = BF, ∵ BDF = ∵ f.