How to solve 5.4x + x = 12.8

How to solve 5.4x + x = 12.8

5.4x+x=12.8
（5.4+1）x=12.8
6.4x=12.8
x=2

How to solve X-60 = 4x / 7?

Multiply 7 on both sides of the equation to get 7x-420 = 4x, shift term to get 7x-4x = 420 to get 3x = 420 x = 140

How to solve x-0.4x = 12

X-0.4X=12
(1-0.4)X=12
0.6X=12
X=12÷0.6
X=20

How to solve (x + 12) * (x + 12) = x * x + 360

(x+12)*(x+12)=x*x+360
x*x+144+24x=x*x+360
24x=360-144=216
x=216/24=9
What do you do downstairs by copying mine

=(sin20°)^2+(sin40°)^2-2sin20°*sin40°*cos120° =(sin120°)^2=3/4.

Structure △ ABC, a = 20 °, B = 40 °, C = 120 °,
From the cosine theorem, a ^ 2 + B ^ 2-2abcosc = C ^ 2,
Using the sine theorem, we get that = (sin ° a) ^ 2 + (SINB) ^ 2-2sin * asinb * COSC = (sinc) ^ 2,
That is, (sin20 °) ^ 2 + (sin40 °) ^ 2-2sin20 * * sin40 * * cos120 ° = (sin120 °) ^ 2

The sum of a certain number and 1:12 is less than 5:4 and the solution of 5-series equations is 3:24
Urgent online, etc

X-1 and 1 / 12 = 5 and 3 / 4-3 and 5 / 24
X = 3 and 5 / 8

Five out of eighteen is a fraction plus a fraction

Five out of eighteen is a fraction plus a fraction
1/6+1/9=5/18

How to solve the equation x + 6 = 3x-4?

x+6=3x-4
6+4=3x-x
10=2x
x=5

Given that a zero point of the function f (x) = x2 + (A2-1) x + (A-2) is larger than 1 and a zero point is smaller than 1, the value range of real number a is______ ．

∵ a zero point of function f (x) = x2 + (A2-1) x + (A-2) is larger than 1, and a zero point is smaller than 1 ∵ f (1) < 0 ∵ 1 + A2-1 + A-2 < 0 ∵ A2 + A-2 < 0 ∵ 2 < a < 1 ∵ the value range of real number a is (- 2,1), so the answer is: (- 2,1)

40% of a number is 0.5 more than one third of it. Find the number? (use the solution of the equation) let the number be x 40% X-1 / 3 * x = 0.5, x = 7.5. Why?

40% of a number is 0.5 more than one-third of it. This sentence means that 40% of X is 0.5 more than one-third of X. that is to say, 40% of x minus one-third of x equals 0.5, so you have the equation 40% X-1 / 3 * x = 0.5, and then through calculation, you can get x = 7.5