2 / 3x-5 / 6 = 3 and another 5 / 13 + 7 / 26-19 / 39

2 / 3x-5 / 6 = 3 and another 5 / 13 + 7 / 26-19 / 39

X = 4 / 23 = 1 / 6 question: what I want is the process. Now I just need the first answer: 2 / 3x = 3 + 5 / 6 2 / 3x = 23 / 6 3x * 23 = 2 * 6 69x = 12 x = 4 / 23

How to solve the equation 3x-25 = 61?

3X-25=61
3X=61+25=86
X=28.6666.

How to solve the equation x + 55 = (3x-55) X4

x+55=(3x-55）4
x+55=4X 3x-4X55
x+55=12x-220
55+220=12x-x
275=11x
x=275/11
x=25

The proof that a is an orthogonal matrix and the adjoint matrix of a is also an orthogonal matrix
Such as the title

Because a is an orthogonal matrix
So a ^ t = a ^ - 1
So a ^ * = det (a) * a ^ - 1 = det (a) * a ^ t
So (a ^ *) ^ - 1 = [1 / det (a)] * (a ^ t) ^ - 1 = [1 / det (a)] * (a ^ - 1) ^ t = [(1 / det (a)) * a ^ - 1] ^ t = (a ^ *) ^ t
So (a ^ *) ^ - 1 = (a ^ *) ^ t
So a ^ * is also an orthogonal matrix
Note: A ^ * denotes the adjoint of A
A ^ - 1 is the inverse of A
A ^ t is the transpose of A

Has or have in the plural

Plural noun followed by have
For singular nouns or the third person, use has after them
Happy New Year_

If the cube of polynomial 9x - the A-2 power of BX + the B + 3 power of ax is a cubic trinomial of X, and it has a variable number term, please try the above a and B to simplify it
Please try the above a and B to simplify the absolute value of A-B plus the absolute value of B + 2
If the cube of polynomial 9x - the A-2 power of BX + the B + 3 power of ax is a cubic trinomial of X, and the number is variable, please try the above a and B to simplify the absolute value of A-B plus the absolute value of B + 2

If the polynomial 9x & sup3; - BX ^ (A-2) + ax ^ (B + 3) is a cubic trinomial of X and has a variable number term, please try the above a and B to simplify | A-B | + | B + 2|
A-2 = 2, B + 3 = 1 or A-2 = 1, B + 3 = 2
That is, a = 4, B = - 2 or a = 3, B = - 1
|A-B | + | B + 2 | = 6 or | A-B | + | B + 2 | = 5

Is the number of nouns countable or uncountable
the amount

The number of people has increased two thous

The visual graph of plane graph is regular triangle. How to draw the original graph

It is known that the intuitionistic graph of a plane graph is an equilateral triangle ABC. The method of making the intuitionistic graph of the original plane graph is as follows: 1. Make the high ad of △ ABC; 2. Extend Da to e, so that AE = ad; 3. Make ef ‖ BC through e; 4. Make the bisector of ∠ ADB intersect EF at point a; 5. Connect a "B and a" C, then △ a "BC is the graph proof: ∫ ad

Write a composition about what family members are doing in the present continuous tense? (50 words)
Seven grade level, 50 words

Today is Sunday,my mother is doing the housework.My father is reading a book.My sister is watching TV.My grandmother is reading a newsparper,and I listenning the music.
Today is weekend. My mother is doing housework. My father is reading. My sister is watching TV
My grandmother is reading the newspaper, and I am listening to music

In the triangle ABC, point D is the midpoint of edge AC, ab = 3aE, BD and CE intersect at point P, let AB = a, AC = B, and use a and B to represent AP

Let BP = λ BD = λ (AC / 2-AB)
EP= μEC= μ（AC-AB/3）
BP=EP-2AB/3=μ（AC-AB/3）-2AB/3
=μAC-（μ/3+2/3）AB
∵BP=BP
∴μAC-（μ/3+2/3）AB=λAC/2-λAB
μ=λ/2,μ/3+2/3=λ
λ=4/5,μ=2/5
AP=AB+BP=AB+4（AC/2-AB）/5
=2AC/5+AB/5
=2b/5+a/5