(6x + 2): (5x-2) = 13:9 how to connect this equation? Fast

(6x + 2): (5x-2) = 13:9 how to connect this equation? Fast


(6x+2):(5x-2)=13:9
13(5x-2)=9(6x+2)
65x-26=54x+18
65x-54x=26+18
11x=44
x=44/11
x=4



Formula method of 9x ^ 2 + 6x + 1 = 0


a=9,b=6,c=1
Then △ = B & # 178; - 4ac = 36-36 = 0
So x = (- 6 ± 0) / 18
So X1 = x2 = 1 / 3



If the image of quadratic function y = AX2 + BX + C (a > 0) intersects with the coordinate axis at (- 1,0) and (0, - 1), and the vertex is in the fourth quadrant, what are the values of a, B and C?
To process! Good solution can be added to 100 points!


The image of y = ax ^ 2 + BX + C (a > 0) intersects the coordinate axis at (- 1,0) and (0, - 1), respectively,
a-b+c=0
c=-1
The vertex (- B / (2a), - (b ^ 2-4ac) / (4a ^ 2)) is in the fourth quadrant
-b/(2a)>0
-(b^2-4ac)/(4a)



Simple calculation of 1234 + 2341 + 3421 + 4123


1234+2341+3412+4123
=1000(1+2+3+4)+100(1+2+3+4)+10(1+2+3+4)+(1+2+3+4)
=10000+1000+100+10
=11110



Given the parabola y = x2 + MX - three fourths M2 (M > 0), it is proved that the symmetry axis of the parabola is on the left side of Y


y=x^2+mx-3/4m^2
=x^2+mx+1/4m^2-m^2
=(x+1/2m)^2-m^2
The axis of symmetry of parabola is x = - 1 / 2m
From M > 0 to - 1 / 2m



Factorization (27 14:46:29)
The difference between the two equations 2x2 - (K + 1) x + K + 3 = 0 is 12 then K=————
Let X1 and X2 be the two real roots of the equation x2 + PX + q = 0, and X1 + 1 and X2 + 1 be the two real roots of the equation x2 + QX + P = 0, then p = -, Q=_____ .
If M and N are the two real roots of equation x2 + 2009x-1, then the value of m2N + Mn2 Mn is --
If a and B are the two real roots of the equation x2 + X-1 = 0, then the value of the algebraic formula A3 + A2B + AB2 + B3 is——————
 


Let one of the roots of the equation be a and the other be a + 12. Then we can get the following result from the Weida's Law: a + (a + 12) = (K + 1) / 2 A * (a + 12) = (K + 3) / 2. We can get the value of K from the above two formulas. 2



Calculation √ 3x ^ 3Y × √ 6y △ 2x
√3x^3y×√6y÷√2x


√3x^3y×√6y÷√2x
=√(3x^3y×6y÷2x )
=3x



50 out of 80 and 11 out of 16, who is bigger?


11 out of 16 is converted into a number whose denominator is 80. The numerator and denominator are multiplied by 5 to get 55 out of 80. The correct answer is 11 out of 16



Let the determinant of a matrix of order 2 be negative, and prove that a can be similar to a diagonal matrix


The conclusion is only true for real matrix, when the two eigenvalues are not equal



Given the dry bulb temperature and wet bulb temperature, is there a simple formula to calculate the relative humidity?
For example, the formula of dry bulb temperature wet bulb temperature multiplied by relative humidity


Look up the table. Don't you have a table? What else do you need!
(dry bulb degree + wet bulb degree) × 0.72 + 40.6 = humidity%