If the exponential function f (x) = (3-A) ^ x, X is a decreasing function in the domain of definition, then the value range of A The more detailed, the better. Time is pressing

If the exponential function f (x) = (3-A) ^ x, X is a decreasing function in the domain of definition, then the value range of A The more detailed, the better. Time is pressing

exponential function
F (x) = a ^ x, X is r
a> 1, monotone increasing
0

Let f (x) = (A-1) x be a decreasing function on R, then the value range of a is___ ．

According to the properties of exponential function: 0 ﹤ A-1 ﹤ 1 ﹤ a ﹤ 2. So the answer is 1 ﹤ a ﹤ 2

The ratio of the distance from a moving point P to a fixed point F (P / 2,0) to the distance from it to a fixed line L: x = - P / 2 is constant E = C / A?

P(x,y)
√(x-p/2)²+y²]==(c/a)|x+p/2|
square
a²x²-a²px+a²p²/4+a²y²=c²x²+c²px+c²p²/4
(a²-c²)x²-(a²+c²)px+a²y²=(c²-a²)p²/4

x^2+210x+10000

X ^ 2 + 210x + 10000 = (x + 105 + 5 times root 41) (x + 105-5 times root 41)

How many days are there from May 22, 2011 to August 20, 2012?

After calculation, 446 days

The resistance of a resistance wire is 12 ohm. When the voltage applied at both ends of the resistance wire is 36V, the electric power will work for 5min, and the electric energy will be consumed

According to Ohm's law, I = u / r = 36 / 12 = 3A,
Power P = UI = 36 * 3 = 108W
Total work w = Pt = 108 * 5 * 60 = 32400j

Find the 100 square digits of 1993, June 1, 1993 is Tuesday, October 1, 1993 is the day of the week?

1) The fifth power of 3 is 3
So the 100th power of 3 is equal to the 5th power and the 20th power of 3
So the 20th power of 3 is equal to the 4th power of 3
So the 100th power of 3 is 1
2）30+31+31+30=122/7=17.3
So it should be Friday

How to express this with letter formula
1 2 3 4 5 6. How to express with letter formula
2n + 1

A = n

1000 divided by brackets 125 divided by 4 brackets

1000/（125/4）=1000*4/125=32

Formula method of a difficult problem in seventh grade mathematics exercise book
1 × 2 × 3 × 4 + 1 = 25 = 5 square
2 × 3 × 4 × 5 + 1 = 121 = 11 square
It is proved that a (a + 1) (a + 2) (a + 3) + 1 = the square of a (a + 3) + 1

a(a+1)(a+2)(a+3)+1=(a^2+3a)(a^2+3a+2)+1
=[(a(a+3)+1)-1][(a(a+3)+1)+1]+1
=Square of a (a + 3) + 1 - 1 + 1 = square of a (a + 3) + 1