Solve the system of inequalities (2x-1) / 3 - (x-3) / 6 > 1, X ≤ (X-2) / 3 + 2, and write the largest integer solution of the system of inequalities

Solve the system of inequalities (2x-1) / 3 - (x-3) / 6 > 1, X ≤ (X-2) / 3 + 2, and write the largest integer solution of the system of inequalities

From (1)
x>5/3
From (2)
3x

9. If there are only four integer solutions to the inequality system of X, then the value range of a is (c)
A． －5≤ ≤－143 B． －5≤ ＜－143
C． －5＜ ≤－143 D． －5＜ ＜－143
Why C?
9. If there are only four integer solutions to the inequality system of X, then the value range of a is (c)
A． －5≤a ≤－143÷3 B． －5≤a ＜－143÷3
C． －5＜a ≤－143÷3 D． －5＜a ＜－143

The result of solving inequality 1
x2-3a
Combined with the two solutions, it is concluded that
2-3a

Eighth grade --- solving 2-variable linear equations 1.4x + 3Y = 245x-y = 302.5x + 3Y = 87x-3y = 4

1、
Equation 1 plus equation 2 times 3,
obtain
4X + 15x = 24 + 90, that is 19x = 114,
So x = 6 and y = 0,
So the solution of the equations is x = 6, y = 0
2、
Equation 1 plus equation 2,
We get 12x = 12, so x = 1,
The solution of the equation is y = 1,
So the solution of the equations is x = 1, y = 1

There are 85 tons of grain in warehouse A and 75 tons in warehouse B. if we want to make the ratio of grain tons between warehouse A and warehouse B 7 to 9, we should

It is set that x tons of grain should be transferred from warehouse A to warehouse B
(85-X)/(75+X)=7/9
7*75+7X=85*9-9X
The solution is: x = 16
16 tons of grain should be transferred from warehouse A to warehouse B

56÷4=14 14÷2=7

7*8=56

5 mathematical problems, solving. Can be simple to calculate
1、5/7+5/7*2
2、47/124*126
3. 24 1 / 13 * 1 / 2
4、17/25*5/27+8/25*17/37+17/37*2/25
5、3/7*5/9+3/7*4/9
Urgent ~
Online, etc

(1) (15 + 5) x = 120 (2) 87 × 99 (simple calculation) (3) 32 × 125 (simple calculation) (4) 78 × 32 + 55 (5) 101 × 87 + 13 × 101 (simple calculation) my own 7395, I hope you can adopt it

The sequence BN is an equal ratio sequence, then B1 + B2 + B3 = 21 / 8, b1b2b3 = 1 / 8, in the sequence an, an = log2bn, find the general term formula of an

We can get the following two values: b1b2b3 = 1 / 8, B1 + B2 + B3 = 21 / 8
B1 = 1 / 8, common ratio = 4. BN = 4 ^ (n-1) / 8 = 2 ^ (2n-5)
an=log2bn=2n-5

Simple operation of 8 / 9 * 5 / 13 + 8 / 13 * 4 / 9

8/9*5/13+8/13*4/9
=8/9*5/13+8/9*4/13
=8/9*（5/13+4/13）
=8/9*9/13
=8/13

In the space quadrilateral ABCD, e, F, G and H are the points on AB, BC, CD and Da respectively. It is known that EF and GH intersect at p. it is proved that EF, GH and AC are collinear

If EF and GH intersect at point P, then p is on EF and GH, and if EF is in plane ABC, then p is in plane ABC. Similarly, GH is in plane ACD and P is in plane ACD, so p must be on the intersection AC of plane ABC and plane ACD, so EF, GH and AC intersect at point P

Fill in the brackets so that the equation holds - 3x ^ 2 + 4 / 2x ^ 2-5x-4 = - 3x ^ 2-4 / ()
2-x/-x^2+3=( )/x^2-3a^2+3a+2/a^2+6a+5=( )/a+5
2-x/-x^2+3=( )/x^2-3 a^2+3a+2/a^2+6a+5=( )/a+5

(-3x^2+4)/(2x^2-5x-4)=- (3x^2-4)/( 2x²-5x-4 )
(2-x)/(-x^2+3)=( X-2 )/(x^2-3)
(a^2+3a+2)/(a^2+6a+5)=( a+2)/(a+5)