The solution equation is: 1 / 6 + 3 / 4 + = 1 / 3 + 1 ②3（x-1）-2（x-1）=4

The solution equation is: 1 / 6 + 3 / 4 + = 1 / 3 + 1 ②3（x-1）-2（x-1）=4

① 1 / 6 + 3x / 4 = 1 / 3 + 1
Multiply by 12
2+9x=4x+12
9x-4x=12-2
5x=10
x=10/5
x=2
②3（x-1）-2（x-1）=4
（x-1）=4
x=4+1
x=5

3x = x + 100, please help me solve the equation

(X-100) = 3x 100 to solve the equation

Solution: get (1-x) / (1 + x) - 3x + 1 ≤ 0
The results showed that (- 3x2-5x) / (1 + x) ≤ 0, br > 0
That is, (3 × 2 + 5 ×) / (1 + x) ≥ 0
There are 3 × 2 + 5x ≥ 0
1 + X ≥0
Or 3 × 2 + 5x ≤ 0
1 +x≤0
Separate solutions for both trade unions
BR>
x∈[-5 / 3,-1]∪[0,∞）

1. The definition field of function y = √ (3x-x ^ 2) is
The answer is [0,3]
How to calculate the value greater than or equal to 0?
2. According to the individual income tax law of our country, every citizen whose monthly income exceeds 840 yuan shall pay individual income tax. If the monthly income exceeds 840 yuan but the excess part does not exceed 500 yuan, the excess part shall be taxed by 5%; if the monthly income exceeds 500 yuan but does not exceed 2000 yuan, the excess part shall be taxed by 10%
(1) The relationship between tax and monthly income of individuals whose monthly income does not exceed 2840 yuan
(2) When the income of the current month is 2000 yuan, what is the taxable amount?

1. If the function is meaningful, the number of square root must be nonnegative
3x-x^2≥0
∴0≤x≤3
The domain is [0,3]
2. Set the monthly income as X Yuan and the tax as y yuan
When x ≤ 840, y = 0
When 840

You are the only one in my heart?

only you in my heart

How many Mu is 522500 square meters?
Do me a conversion

5225 (10000 m2) / 666 = 784.53453453453 Mu

It is known that the square of 2 + 2K of 2k-3 ＞ 1 is a linear inequality with respect to x, then the solution set of k = () inequality is ()

∵ (2k-3) x & # 178; + 2K & # 178; x > 1 is a simple inequality about X
∴2k-3=0
==> k=3/2
The inequality is: 9x / 2 > 1
x>2/9

English translation
Translation at middle school level

Can you tell me how to go to the nearest bus station?
If you are polite, you can add an exception me in front of it
If you look at my low level, give it to me

How to prove that the square difference of any two odd numbers is a multiple of 8

As shown in the picture

Let f (U, V) be a differentiable function of two variables, z = f (x ^ y, y ^ x), and find the partial derivatives of X and y

Let u = x ^ y v = y ^ x
dz/dx=dz/du*du/dx+dz/dv*dv/dx
=df/du*y*x^(y-1)+df/dv*lny*y^x
dz/dy=dz/du*du/dy+dz/dv*dv/dy
=df/du*lnx*x^y+df/dv*x*y^(x-1)