When what is the value of K, is the inequality half * (KX + 8) greater than 3x always true?

When what is the value of K, is the inequality half * (KX + 8) greater than 3x always true?

(KX + 8) / 2 > 3x double 2
kx+8>6x
(6-k)x0
So when k = 6, half of the inequality * (KX + 8) is greater than 3x

When k is the value, the inequality 1 / 2 (KX + 8) is greater than 3x

When k = 6
1 / 2 (KX + 8) is greater than 3x
KX + 8 is greater than 6x
(K-6) x is greater than - 8
When K-6 = 0, the inequality holds
So k = 6

Given that the inequality 3x ^ 2 + KX + 3K / x ^ 2 + X + 2 > 2 holds for all real numbers x, then the value range of K is?

(3x^2+kx+3k)/(x^2+x+2)-2>0
[x^2+(k-2)x+(3k-4))/(x^2+x+2)>0
The denominator x ^ 2 + X + 2 is always greater than 0
So the molecular constant is greater than zero
So the discriminant is less than 0
(k-2)^2-4(3k-4)

The solution of the inequality KX + 3K with respect to X is greater than 0 (where the constant k is not equal to 0)

kx+3k>0
kx>-3k
If k > 0, divide the two sides by K, and the inequality remains unchanged
x>-3
If K

At present, there are 16 different cards, including 4 red, 4 green, 4 yellow and 4 blue. Three of them are required to be of different colors and at most one is red,
What is the number of different methods?

No red
4*4*4=64
1 red
4*4*4*3=192
64+192=256

60 ~ 80 grams of alcohol is equivalent to what people often call a few Jin of wine
Take 45 degrees of Baijiu for example. How many pounds of alcohol is equivalent to 80 grams of alcohol?

Generally speaking, a jin of wine actually means 500ml
The alcohol content of 45 degree 1 jin wine is the highest
500*0.45=225ml
At room temperature, the alcohol density was 0.8g/ml
So the alcohol weight of 1 jin wine is 0.8 * 225 = 180g
80/180=0.44
So 80g alcohol is equivalent to 4 and a half of the baijiu.

4. Measured from the inside, the diameter of the bottom of the cup is 8 cm and the height is 15 cm. The net content of purified water is 18.9 liters. How many glasses of water can a bucket of purified water hold?
Please write down the formula and the result of the above question completely,
5. A cylindrical oil barrel, measuring from the inside, has a diameter of 40 cm and a height of 50 cm
(1) What's its volume in liters?
(2) If one liter of diesel weighs 0.85 kg, how many kg of diesel can be loaded in this oil barrel?
Please write down the formula and the result of the above question completely,

3.14*4^2*15=18900
3.14*0.2^2*0.5
The answer to the previous question is multiplied by 0.85

Let's talk about 10 calculation questions (formulas) (answers) in the first semester of junior high school
The better + the more points

The value is π=__________ (4) 3.1416 the approximate value of retaining three significant numbers is_____________ ;
（3） Judgment questions:
(1) The accuracy of the approximate number 25.0 is one, and the significant number is 2,5; (2) the accuracy of the approximate number 4000 is the same as that of the approximate number 4000; (3) the accuracy of the approximate number 4000 is the same as that of the approximate number 4 * 10 ^ 3; (4) the accuracy of the approximate number 9.949 to 0.01 is 9.95
Exercise 8 (Level B)
（1） Use the rounding method to approximate the following numbers (three significant numbers are required): (1) 37.27 (2) 810.9 (3) 0.0045078 (4) 3.079
（2） Use the rounding method to approximate the following numbers: (1) 37890.6 (2) 213612.4 (3) 1906.57
nine
9x^2(x-1)^2-3(x^2-x)-56
=9x^2(x-1)^2-3x(x-1)-56
=[3x(x-1)-8][3x(x-1)+7]
=(3x^2-3x-8)(3x^2-3x+7
I wish you progress in your study! My hands are sore

How many square meters and acres is 1260 meters perimeter equal to

Circle: radius = 1260 / 2 μ m, area = Wu * (1260 / 2 μ) (1260 / 2 μ) = 12500 M2 = 12500 / 666 and 2 / 3 = 18.75 Mu = 125 mu, square: side length = 1260 / 4 = 315 m, area = 315 * 315 = 99225 M2 = 148.8375 Mu = 99.225 mu, rectangle: 1260 / 2 = 630 m, length x, width 630-x, area = (630 x-x Square) m2 = (630 x-x Square) / 100 mu = (630 x-x Square) / 666.67 mu

Sixth grade first semester mathematics test paper (2) unit 2 review additional question 2 is very urgent, please see the people will help me, I hope you can write the formula clearly!
The edge length of the three squares is 2cm.2cm.5cm respectively. If they are glued together, a new object can be obtained. How to minimize the surface area of the new object? (draw a picture) what is the minimum surface area of the new object?

5×5×6=150
2×2×6=24
150+24=174
The answer is 174
I'm in grade six, too
Hope it helps