If the inequality Xa (a is not equal to b), then what is the solution set of the inequality system x2-a

If the inequality Xa (a is not equal to b), then what is the solution set of the inequality system x2-a

The discussion was based on different situations,
If 0

Urgent! Given f (x) = {1 (x is greater than or equal to 0), - 1 (x is less than 0)}, solve the inequality x + (x +!) f (x + 1) less than or equal to 5

x>=-1
x+1>=0
Then f (x + 1) = 1
So x + (x + 1)

Several factorization problems in grade two of junior high school
1.(a+b)²+6a(a+b)+9a²
2.3y²+9y-12
3.(x²+4)²-16x²
4.3x²-7x-6
&Sup2; can be copied, do not use ^

1.(a+b)²+6a(a+b)+9a²
=(a+b+3a)²
=(4a+b)²
2.3y²+9y-12
=3(y² +3y-4)
=3(y+4)(y-1)
3.(x²+4)²-16x²
=(x² +4)² -(4x)²
=(x² +4x+4)(x² -4x+4)
=(x+2)² (x-2)²
4.3x²-7x-6
=(3x+2)(x-3)

In the plane rectangular coordinate system, the right vertex of the right triangle is placed at point P

(1) Find the value of OA ob (2) rotate the right triangle anticlockwise around point P, and the two right angles are equal to the square of the square of the square 4 of the coordinate axis (1) (oa-4), the square of the square of the square 4 (4-ob) = the square of the square OB of OA

(4x-1) ^ 2-10 (4x-1) - 24 = 0.9x ^ 2 = 4 (3x + 1) the solution of these two problems, urgent ah~~~~~~
Give it 20 points~~~~~~~~~~
(4x-1)^2-10(4x-1)-24=0
9x^2=4(3x+1)

These two problems are about the quadratic equation of one variable. We can first simplify them into the standard form ax ^ 2 + BX + C = 0
The specific process is as follows:
1. The original equation can be reduced to 16x ^ 2-48x-13 = 0, and then factorized to (4x + 1) (4x-13) = 0. If the product is 0, then 4x + 1 = 0 or 4x-13 = 0, and the solution is x = - 1 / 4 or x = 13 / 4
For the second course, you can do it yourself as an exercise. However, after simplification, it is not easy to decompose the factor. You can use the root formula method to solve it. You should know it. If you don't know, you can continue to ask me

If the line y = x + B intersects the parabola y = 1 / 2x & # 178, at two points a and B, O is the vertex of the parabola and OA is perpendicular to ob, then the value of real number B is

The formula of encounter problem

Encounter time: total distance / speed and

The moving point P is above the x-axis, and the square of the distance from it to the line x + Y-1 = 0 is equal to the distance from it to the y-axis

Let the coordinates of point p be (x, y)
The square of the distance from it to the straight line is; (x + Y-1) ^ 2 / 2
The distance from it to the y-axis is | X|
So there is a trajectory equation: (x + Y-1) ^ 2 / 2 = | x |,
Above the x-axis, it indicates that Y > 0

①3x²+6xy+3y²
②1-x+x²/4
③-4a²x²+12ax-9
④(a-2b)²-14（a-2b)+49
⑤(a+b）²-4ab
⑥（x-y）²-4（x-y-1）

①3(x²+2xy+y²)=3(x+y)²
②﹙1／2x－1﹚²
③﹣(2ax－3)²
④(a-2b-7）²
⑤(a-b）²
⑥（x-y-2）²

How many days are there from October 28, 2011 to April 22, 2012?

4+30+31+31+29+31+22=178