1 / 2, 1 / 3, 3 / 2, 5 (), (), 9 and 11

1 / 2, 1 / 3, 3 / 2, 5 (), (), 9 and 11

Half, 1, 3, 3 / 2, 5 (7), (5 / 2), 9, 11
Starting from the first number, add 1 every two
Starting from the second and third numbers, add 2 every other number

Fill in 2, - 1, half, quarter according to the rule

One in eight, one in 16. This is what I do. I don't know if it's right. If it's wrong, it's one in eight, one in 16

1 and 2 / 3 - [(3.62 × 2 / 15 + 6.38 △ 7 and 1 / 2) × 1.82 - 1 and 1 / 3 × 0.82]

1 and 2 / 3 - [(3.62 × 2 / 15 + 6.38 △ 7 and 1 / 2) × 1.82 - 1 and 1 / 3 × 0.82]
=5/3-【（3.62*2/15+6.38*2/15）*1.82-4/3*0.82】
=5/3-【2/15*（3.62+6.38）*1.82-4/3*0.82】
=5/3-【4/3*1.82-4/3*0.82】
=5/3-4/3*【1.82-0.82】
=5/3-4/3
=1/3

N is a positive odd number and can be divided by 3

All natural numbers are in one of the following six formulas
1.6n
2.6n-1
3.6n-2
4.6n-3
5.6n-4
6 N-5 (where n is a natural number)
Among them, 1,3,5 are even numbers, 2,4,6 are odd numbers
So the general formula of positive odd number and divisible by 3 is 6n-3, and the remainder of it divided by 6 must be 3

It is known that P is a point on the ellipse x2a2 + y2b2 = 1 (a > b > 0) with F1 and F2 as the focus. If Pf1 ⊥ PF2, Tan ∠ pf1f2 = 12, then the eccentricity of the ellipse is ()
A. 12B. 23C. 13D. 53

Let | Pf1 | = m, then Tan ∠ pf1f2 = 12 | PF2 | = m2, | F1F2 | = 52m, | e = CA = 53, so choose D

Which two prime numbers are equal to 14

2 7

Solving inequality / loga (X-2) / > loga (2-x) (0

The inequality │ loga (X-2) │ ＞ loga (2-x) has the same solution as loga (X-2) ＞ loga (2-x) or loga (X-2) ＜ - loga (2-x) loga (X-2) ＞ loga (2-x) or loga (X-2) ＜ loga [1 / (2-x)] and 0 ＜ a ＜ 1  0 ＜ X-2 ＜ 2-x or X-2 ＞ 1 / (2-x) ＞ 0

For the image of inverse scale function y = 4x, the following statement is correct: A. it must pass through point (1,1) B. two branches are distributed in the second and fourth quadrants C. the two branches are axisymmetric with respect to the X axis D. the two branches are centrosymmetric with respect to the origin

A. Substituting (1,1): left ≠ right, so option a is wrong; B, k = 4 ＞ 0, the image is in the first and third quadrant, so option B is wrong; C, fold along the X axis is not coincident, so option C is wrong; D, two curves are symmetrical about the origin, so option D is correct; so option D

It is known that A.B represents the number A.B. the distance between two points of A.B can be expressed as | ab |, and | ab | = | A-B |
(1) The distance between the two points representing 2 and 5 on the number axis is, the distance between the two points representing - 2 and - 5 on the number axis is, and the distance between the two points representing 2 and - 7 on the number axis is
(2) If | ab | = 2, then x is
(3) When the formula | x + 1 | + | X-2 | takes the minimum value, the corresponding value range of X is;
When the formula | x + 1 | + | X-2 | + | X-5 | is the minimum, the corresponding value range of X is

1、3；3；9
2. |x + 1|; X is 1 or - 3
3. When x is greater than or equal to - 1 and less than or equal to 2, - 1 ≤ x ≤ 2;
x=2
Honey,

Probability density in probability theory
It is known that the probability density of random variable (x, y) is f (x, y) = 12Y * y, 0