Solving the equation: x-one-third = one-half plus one-half

Solving the equation: x-one-third = one-half plus one-half

x-1/3=1/2+1/2
x=1+1/3
x=4/3

Given | x + 2 | = 0, | Y-3 | = 0, find the value of negative two and one-half x-five-thirds y + 4xy

|x+2|=0,|y-3|=0
The solution is as follows
x=-2 y=3
Negative two and one half x = - 5x / 2
The original formula = - 5x / 2 * 5Y / 3 + 4xy
=-25xy/6+24xy/6
=-xy/6
=-(-2)*3/6
=1

|X-1 | + | y + 3 | = 0, then the value of y-x-half is () 1. - four and half 2. - two and half 3. - one and half 4. One and half% d% a

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In the quadratic function y = ax & sup2; + BX + C, a ＞ 0, B ＜ 0, C ＜ 0, is to judge the positive and negative of 2A + B?
How to judge?

The axis of symmetry x = - B / 2a, when - B / 2A ＞ 1, because a ＞ 0, multiply to get 2A + B ＜ 0,
Similarly: when - B / 2A < 1 is, because a > 0, multiply it to get 2A + b > 0

Given f (x) = (X-2) 2, X ∈ [- 1, 3], find the monotone decreasing interval of function f (x + 1)

The function f (x + 1) = [(x + 1) - 2] 2 = (x-1) 2 = x2-2x + 1, X ∈ [- 2, 2], so the monotone decreasing interval of the function is [- 2, 1]

Given a 2-B 2 = 0 and ab ≠ 0, the value of the fraction a 2-3ab + 5B 2 / a 2-2ab + 4B 2 is obtained

AP and BP divide the complementary angle cam and CBD of angle CAD equally. Please write the relationship between angle P, angle c and angle D directly without giving reasons
I can't make a picture,

∠P=180-∠PBE-∠PEB
=180-1/2(180-∠C-∠CGB)-∠AED
=90+1/2∠C+1/2∠CGB-(180-∠D-∠DAE)
=1/2∠C+1/2∠CGB-90+∠D+(∠DAG+1/2∠CAM)
=1/2∠C+1/2∠CGB-90+∠D+(180-∠D-∠DGA)+1/2(∠D+∠DGA)
=90+1/2∠C+1/2∠D

How much is 3.07 kg

3.07kg = 3070g = 0.00307t

A rectangular playground, after expansion, the length and width are increased by 10 meters and the area is increased by 800 square meters

（800-10×10）÷10×2
=700÷10×2
=140m