1.1 by 1.2 by 13 by 14 by 15 (simple calculation) Off form calculation (simple calculation)
This is simple. Let me teach you
1.1 times 1.2 times 13 times 14 times 15 = 0.01 * 11 * 12 * 13 * 14 * 15
=0.01*(13-2)*(13-1)*13*(13+1)*(13+2)
=0.01*13*(169-1)(169-4)
=0.13*168*165
=1.3*84*33=1.3*12*7*11*3=11*13*7*3.6
=143*7*3.6
=1001*3.6
=3 603.6
I can't do anything about the following. I can only do it in writing
The final result is 3 603.6
Do you understand the above? The main test is the square difference formula!
The parabolic equation y = - 0.5x * 2 + m, points a and B and P (2,4) are on the parabola, and the inclination angles of the lines PA and Pb are complementary. It is proved that the slope of the line AB is fixed
P (2,4) is on the parabola, which is carried into y = - 0.5x ^ 2 + m, M = 6,
Parabolic equation y = - 0.5x ^ 2 + 6
Suppose the inclination angle A1 of the straight line PA and the slope K1 = tga1;
The slope of line PA is K2 = tga2 = TG (180-a1) = - tga1 = - K1
Suppose a (x1, - 0.5x1 ^ 2 + 6), B (X2, - 0.5x2 ^ 2 + 6); P (2,4)
And K2 = - K1
(-0.5x1^2+6-4)/(x1-2)=-(-0.5x2^2+6-4)/(x2-2)
After simplification, X1 + x2 = - 4
Slope of line AB:
k=〔(-0.5x2^2+6)-(-0.5x1^2+6)〕/(x2-x1)
=-0.5(x1+x2)
=-0.5×(-4)
=2
Get proof
How much is one eighth minus one half minus one third?
One third
The quadratic function y equals 2x square minus 4x minus 6 is transformed into y equals a (X-H) square by using the collocation method
y=2(x-1)^2 -4
Add brackets to the following formula to make the equation hold. 9 × 0.6 + 4.8 △ 0.4 ― 0.3 = 486
9*(0.6+4.8)\(0.4-0.3)=486
The minimum value of the formula | x + 5 | is () which means that the value of X is ()
The minimum value of the formula | x + 5 | is (0), which means that the value of X is (- 5)
(6.4 times 5 times 8.1) divided by (3.2 times 2.5 times 2.7)
Simple calculation with computer
(6.4*5*8.1)/(3.2*2.5*2.7)
=(3.2*2*2.5*2*2.7*3)/(3.2*2.5*2.7)
=2*2*3
=12
How do polynomials and polynomials multiply
For example: (4a + 5b) x (2n + 4m)
=4a x 2n+4a x 4n+5b x 2n+5b x 4m
=8an+16am+10nb+20bm
To prepare 1000 grams of 80% alcohol into 60% alcohol, a student added 300 grams of water without consideration
Try to explain whether the student added too much water through calculation?
If the water is excessive, how many grams of 95% alcohol should be added? If the water is insufficient, how many grams of 20% alcohol should be added?
1000*80%/(1000+300)=61.5%
So the water is not too much. Not enough
Water shortage, add 20% alcohol x G
There are
(1000*80%+x*20%)/(1000+300+x)=60%
The solution is x = 50
So you need to add 50 grams
6 out of 7, 9 out of 21, 9 out of 6
6 out of 7 = 36 out of 42
9 out of 21 = 18 out of 42
9 out of 6 = 63 out of 42