The problem of quadratic equation of two variables: it is known that the solution of 2x + 3Y = 0, 4x-2y = 3-A is x = 3, y = - 2, Given that the solution of 2x + 3Y = 0 4x-2y = 3-A is x = 3 y = - 2, then a =?

The problem of quadratic equation of two variables: it is known that the solution of 2x + 3Y = 0, 4x-2y = 3-A is x = 3, y = - 2, Given that the solution of 2x + 3Y = 0 4x-2y = 3-A is x = 3 y = - 2, then a =?

a=-13

There are () solutions to the quadratic equation 2x + y = 4, and the points whose coordinates are in the image of the linear function ()

The bivariate linear equation 2x + y = 4 has (innumerable) solutions, and the points whose coordinates are all on the image of the linear function (y = - 2x + 4)

The points whose coordinates are the solutions of the quadratic equation 2x + y = 5 are all on the image of the linear function ()
The coordinates of any point on the line y = - 2x + 5 are suitable for the equation ()

The points whose coordinates are the solutions of the bivariate linear equation 2x + y = 5 are all on the image of the linear function (y = - 2x + 5)
The coordinates of any point on the line y = - 2x + 5 are suitable for the equation (2x + y = 5)

The denominator of the equation 2-one-third X-1 = 5 + two-thirds 1-2x is removed

Multiply both sides of the equation by 6
12-2(x-1)=30+3(1-2x)
4x=23
x=23/4
=5.75

The ratio of a and B is 3:5. The difference between B and a is 120. What's the number of B?

Number b = 120 △ (5-3) × 5 = 60 × 5 = 300

If a > 0, b > 0 and 2A + B = 4, then the minimum value of 1ab is 0______ ．

Because a > 0, b > 0, so AB = 12 × 2Ab ≤ 12 (2a + B2) 2 = 12 × 22 = 2, so 1ab ≥ 12

The ratio of a and B is 9:2. The number of a is 56 more than that of B. what is the number of a? What is the number of B?

Regard party A and Party B as 9 copies and 2 copies respectively
Then a is 7 more than B, each = 56 / 7 = 8
A = 8 * 9 = 72
B = 8 * 2 = 16

Let α 1 and α 2 be the solutions of the non-homogeneous linear system AX = B, and β be the solutions of the corresponding homogeneous system AX = 0, then AX = B must have a solution ()
A、α1+α2β B、α1-α2 C、β+α1+α2 D、β+1/2α1+1/2α2

Because β is the solution of the corresponding homogeneous system AX = 0, the solution of non-homogeneous linear system AX = B can be expressed as α = k β + s, where s is the special solution of non-homogeneous linear system AX = B. let α 1 = m β + s, α 2 = n β + s, then β + 1 / 2 α 1 + 1 / 2 α 2 = (1 + (M + n) / 2) β + S = k β + s

A, B and C jointly process 120 parts. The number of parts processed by a is 2 / 1 of that processed by B and C, the number processed by B is 3 / 1 of that processed by a and C, and the number processed by C is 7 / 5 of that processed by a and B. how many parts are processed by a, B and C

A + B + C = 120
A = (1 / 2) * (B + C)
B = (5 / 7) * (a + C)
The solution is as follows
A = 40, B = 50, C = 30

How to solve 0.52-x = 0.3 of equation quickly

x=0.52-0.3
x=0.22