If the solution of the equation system {4x-y = 1} is {x = 2}, then the intersection coordinates of the images of the first-order functions y = 4x-1 and y = 2x + 3 are___ y=2x+3 y=7

If the solution of the equation system {4x-y = 1} is {x = 2}, then the intersection coordinates of the images of the first-order functions y = 4x-1 and y = 2x + 3 are___ y=2x+3 y=7


4x-y = 1 y = 4x-1
If the X and Y axes of two functions are the same, it is to solve a system of equations
So, the solution of the equations is the intersection coordinates (2,7)



The quadratic equation 4x-y-7 = 0 is written as a linear function


Let y = 4x-7



Given the quadratic equation 2x + 3Y + 6 = 0, the algebraic expression of X is used to express y, and Y is regarded as a function of X, and its image is drawn
(1) When x = - 6,3, the value of Y
(2) When y = - 2,4, the value of X
(3) When y = 0, what is the corresponding value of X? Which equation of first degree with one variable is it


(1) When x = - 6,3, the value of Y is 2, - 4
(2) When y = - 2,4, the value of X is 0, - 9
(3) When y = 0, the corresponding value of X is - 3, which is the solution of the linear equation of one variable 2x + 6 = 0



There are 85 tons of grain in warehouse A and 75 tons in warehouse B. if the ratio of grain in warehouse A and warehouse B is 7:9, how many tons of grain should be transferred from warehouse A to warehouse B?


A total of 85 + 75 = 160 tons
Now a has 160 (7 + 9) X7 = 70 tons
Transferred 85-70 = 15 tons from warehouse A



7 / 8X1 / 14 = 5 / 12 divided by 5 = 9 divided by 3 / 4 = 10 divided by 2 = 56 divided by 2 / 3=


7/8*1/14=1/8*1/2=1/16
5/12*1/5=1/12
9*4/3=3*4=12
10*1/2=5
56*3/2=28*3=84



Let's take a look at these calculations. Can they be operated easily? Yes, I hope I can write down the process
①8.4÷5.6×3.2 ②6.12÷4.5-0.93 ③0.75×16÷0.32 ④3.45+7.2÷0.24 ⑤64.2-49.7÷1.4


①8.4÷5.6×3.2 =(1.2X7)÷(0.8x7)x3.2=1.2÷0.8x3.2=1.5x3.2=4.8 ②6.12÷4.5-0.93 =1.36-0.93=0.43 ③0.75×16÷0.32 =12÷0.32=37.5 ④3.45+7.2÷0.24 =3.45+30=33.45 ⑤64.2-49.7÷1.4=64.2-35.5=28.7



It is known that the sum of the first three terms of the equal ratio sequence {an} is equal to 7, and the product is equal to 8


When A2 = 2, A1 = 2 / Q, A3 = 2q, then a1 + A2 + a3 = 7,2 / Q + 2q + 2 = 72 / Q + 2q-5 = 02q ^ 2-5q + 2 = 0 (2q-1) (Q-2) = 0q = 1 / 2 or q = 2An = 2 ^ n-1 or an = 1 / 2 ^ n-1 = 2 ^ 1-N, then q = 2 or q = 0.5 can be obtained by substituting a1 + A2 + a3 = 7,2 / Q + 2q + 2q + 2q-5 = 02q ^ 2-5q + 2 = 0 (2q-1) (Q-2) = 0q = 1 / 2 or q = 2An = 2 ^ n-1 or an = 1 / 2 ^ n-1 = 2 ^ 1-n



The simple calculation of 8 / 15 △ 3 / 25-5 / 7 × 21 / 50 is adopted


=8 / 15 × 25 / 3-3 / 10
=40 / 9-3 / 10
=400 out of 90-27 out of 90
=373 out of 90



It is known that Mn is the median line of ladder shaped ABCD. AC, BD and Mn intersect at F, e, ad = 30cm, BC = 40cm. Calculate the length of EF


Mn is the median of ladder shaped ABCD
∴MN//AD//BC
∵MA=MB,∴BE=ED
Similarly, AF = FC
In △ ABC
∵MA=MB,FA=FC
∴MF=BC
In △ abd
∵MA=MB,EB=ED
∴ME=AD
∴EF=MF-ME=BC-AD
=×40-×30=5(cm)
\(^ o ^) / ~ pick me!



1 / 6 = 1 / () + 1 / () fill in two different natural numbers in brackets to make the equation hold


1 / x + 1 / y = 1 / 6 to 6x + 6y = xy and x > 6, Y > 6
The answer is put in by yourself
10 15