The four equations x + by = 8,2x-y = 7,3ax-5by = 9, - 3x + y = - 6 have the same solution, and the values of a and B are obtained

The four equations x + by = 8,2x-y = 7,3ax-5by = 9, - 3x + y = - 6 have the same solution, and the values of a and B are obtained

simultaneous
2x-y=7,
-3x+y=-6
obtain
x=-1,y=-9
Put it into the other two equations
-1-9b=8,b=-1
-3a-5*(-1)*(-9)=9,a=-18

When m is an integer, the solution of the equation 3x + m-2 (m-2) = 3M + X is less than 5

M > 3.5

What is the value of M? The solution of the equation 4x-2m = 3x + 1 is twice that of x = 2x-3m?
The equation of first degree with one variable,

m=1/4

The algebraic expressions a2-2ab + B2 and (a-b) 2 are obtained, where 1. A = 1 / 2, B = 3.2, a = 5, B = 3
Look at two algebras. What do you find?
Using the law you found, find out 1.437 & # 178; - 2 * 1.437 * 0.437 + 0.437 & # 178;

1.a=1/2,b=3a²-2ab+b²=1/4-2×1/2×3+9=1/4-3+9=1/4+6=25/4(a-b)²=（1/2-3）²=（-5/2）²=25/42.a=5,b=3 a²-2ab+b²=5²-2×5×3+3²=25-30+9=4（a-b）²=（5-3）...

(4) As shown in Figure 4, AP and BP divide ∠ cam and ∠ CBD equally, and directly write the relationship between ∠ P and ∠ C and ∠ d without giving reasons

What about the picture? Take a picture

How many kilograms is 3.45 tons

3.45 tons equals 3450 kg

The perimeter of a rectangular playground is 300 meters. Now the length and width of the playground will be increased by 10 meters respectively. The area of the increased part is 300 meters______ Square meters

Suppose: the length of the original playground is a meter and the width is B meter. The sum of the length and width of the original playground is 300 △ 2 = 150 (meters), that is, a + B = 150 (meters). The length of the increased playground is a + 10 (meters), the width of the increased playground is B + 10 (meters), and the increased area is 10 × (B + 10) + 10a, = 10 × (a + B + 10), = 10 × (150 + 10), = 10 × 160, = 1600 (square meters) ）A: the additional area is 1600 square meters

In △ ABC, ab = 12cm, AC = 18cm, points D and E are on AB and AC respectively,
If △ ade and △ ABC can be similar, and ad = 4cm, calculate the length of AE

△ABD∽△ABC
1）∠ADE = ∠B,∠AED = ∠C
∴AD：AB = AE：AC
∴4：12 = AE：18
∴AE = 6cm
2）∠ADE = ∠C,∠AED = ∠B
∴AD:AC = AE :AB
∴4：18 = AE：12
∴AE = 8/3 cm
 AE = 6cm or 8 / 3cm

In the activity of donating money to the earthquake stricken area, Xiao Fang took out half of his pocket money and donated more than one yuan to the children in the disaster area, leaving 12 yuan
How much was it?

(12 + 1) * 2 = 26 yuan

As shown in the figure, for flagpole AC, the elevation angle of a at the top of flagpole is 30 ° measured at B, and the elevation angle of a measured at d is 45 ° when the flagpole reaches D 10 m ahead, how many meters is the flagpole high

Let DC = AC = X;
Because the angle ABC = 30 °, ab = 2x;
BC=BD+DC=10+x；
Because AC = x, BC = √ 3x = 10 + X;
So x = 10 / (√ 3-1) = 5 (√ 3 + 1)