(98-x) + 3 = x-3, how to solve the equation

(98-x) + 3 = x-3, how to solve the equation

(98-X)+3=X-3
98-x+3=x-3
2x=104
x=52
If you have any mistakes, please correct them,
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What is the equation whose solution is x = 3 in the following equation?
1`-2-6=0 2`/X+2/=5 3`(X-3)(x-1) 4`1/3x=x-2
A ` one B · two C · three D · four

Choose a
-2-6 = 0, no unknowns
/The solution of X + 2 / = 5 is x = - 7 or x = 3
3 '(x-3) (x-1) = 0, the solution is x = 3 or x = 1
The solution of 4 ` 1 / 3x = X-2 is x = 3

The solution of equation (x-4) (x-3) is

4 or - 3

Given that there is no intersection point between the image of the first-order function y = - x + 4 and the inverse scale function y = KX in the same rectangular coordinate system, the value range of K is ()
A. k＞0B. k＜4C. k＞-4D. k＞4

By solving the equations y = − x + 4, ① y = KX, ②, and substituting ① into ②, we get - x + 4 = KX. After sorting out, we get x2-4x + k = 0, ∵ there is no intersection point between the image of the first-order function y = - x + 4 and the inverse proportion function y = KX in the same rectangular coordinate system, ∵ Δ= 16-4k < 0, ∵ k > 4

It is known that the coefficient with X term in the expansion of F (x) = (1 + 2x) ^ m + (1 + 2x) ^ n (m, n ∈ n *) is 24, and the minimum value of the coefficient with x ^ 2 in the expansion is obtained

f(x)
=1+(2x)^m+1+(2x)^n
Because in the expansion of (1 + 2x) ^ m + (1 + 2x) ^ n (m, n ∈ n *), the coefficient with X term is 24
And because 24 is not equal to 2 ^ n
So m = 3 N = 2 or M = 2 n = 3
The degree of x ^ 2 is 0

Given a + B = 2 / 3, ab = - 2, find the square of (a-b)

Because a + B = 2 / 3 AB = - 2, so (a + b) ^ 2 = 4 / 9, that is: A ^ 2 + B ^ 2 + 2Ab = 4 / 9, so a ^ 2 + B ^ 2-2ab = 4 / 9-4ab, that is: (a-b) ^ 2 = 76 / 9

12 (x square + 1 / 2 of x) - 56 (x + 1 / 2 of x) + 89 = 0

In this paper, 12 (x (x \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\x = 1 /

Solving equation 3 = - 6x

3=－6X
6x=-3
x=-3/6
x=-1/2

There is a column of numbers: A1, A2, A3 If A1 = 2, then a2007 is ()
A. 2007B. 2C. 12D. -1

According to the meaning of the question: A1 = 2, A2 = 1-12 = 12, A3 = 1-2 = - 1, A4 = 1 + 1 = 2; period is 3; 2007 △ 3 = 669; so a2007 = A3 = - 1

Let - 1 ≤ x ≤ 7, simplify: √ X's Square - 14x + 49 - √ X's square + 2x + 1

Square of X - 14x + 49 - square of X + 2x + 1
=√(X-7)^2-√(X+1)^2
x≤7
X-7≤0
0≤7-X
-1≤x
0≤X+1
Original formula = 7-x - (x + 1) = 7-x-x-1 = 6-2x