(5-x-2 of X-2) / 3-x of 3x-6 (5 / 2 of X-2) - X-2) / (3 / 6 of 3x-x)

(5-x-2 of X-2) / 3-x of 3x-6 (5 / 2 of X-2) - X-2) / (3 / 6 of 3x-x)

=3-x of X-2) / 3x-6 of 3-x, 3x-6 = 3 (X-2) X-2
=3

1 / x + 1 / 2x + 1 / 3x = 1 calculate 1 / x + 1 / 2x + 1 / 3x

1/x+1/2x+1/3x=1
6/6x+3/6x+2/6x=1
11/6x=1
x=11/6
It is proved that x = 11 / 6 is the solution of the equation

Calculation: 1-2x + (- 2 / 3x) - (1-4 / x)

1-2x + (- 2 / 3x) - (1-4 / x)
=1-2X-3\2X-1+1\4X
= -2X-6\4X+1\4X
= -2X-5\4X
= -13\4X
13X minus 4

Determinant calculation
c a d b
a c d b
a c b d
c a b d

0
The first line minus the fourth line, the second line minus the third line, the first two lines are
0 0 d-b b-d
0 0 d-b b-d
Because the first two lines are the same, it is 0

(11 / 18 plus 8 / 9) multiply by 2 / 3 divided by 2

The limit X of 1 / (1-x) - 3 / (1-x ^ 2) approaches 1

When x approaches 1, the limit does not exist

Simple calculation of 12 / 13 × 9 / 11 + 12 / 11 × 2 / 13
emergency

12/13×9/11+12/11×2/13
=12/13×9/11+12/13×2/11
=12/13×(9/11+2/11)
=12/13×1
=12/13

Factorization speed of a ^ 2 + 2Ab + B ^ 2

(a+b)^2

Simple operation of dividing 66 and 25 by 13

66 1 / 25 △ 13
=(65 + 1 and 1 / 25) △ 13
=65÷13+26/25÷13
=5+2/25
=5 and 2 / 25

It is known that the straight line L passes through the point O (1,1) and the inclination angle a = 30 degrees. (1) write out the parameter equation of L
(2) Let L and circle x ^ 2 + y ^ 2 = 4 intersect at two points a and B, and find the product of the distances from P to two points a and B

1. (Y-1) / (x-1) = Tan 30 degree = sin 30 degree / cos 30 degree
So Y-1 = ksin30 degrees; X-1 = kcos30 degrees
Namely
X = 1 + KCOs 30 degrees
Y = 1 + ksin30 degrees
K is a parameter belonging to R
2. What about the coordinates of P
I see. P should be o point Sweat
The parametric equation of the line XY is introduced into the circle
K ^ 2 + (root 3 + 1) K-2 = 0
Then OA * ob = - vector OA dot multiplied by vector ob (the following "degree" is omitted)
=-(k1cos30,k1sin30)(k2cos30,k2sin30)
=-(0.75k1k2+0.25k1k2)
=-k1k2
From the great theorem, k1k2 = - 2
So OA * ob = 2